java从键盘输入一个大于1的整数时,计算小于该整数的所有奇数的

importjava.util.Scanner;publicclassDemo{publicstaticvoidmain(String[]args){Scannersc=newScanner(Syst

importjava.io.*;importjava.util.*;classMain{publicstaticintgcd(intm,intn){while(true){if((m=m%n)==0)

packagetest1;importjava.util.Scanner;publicclassTest6{publicstaticvoidmain(String[]args){Scannerinpu

importjava.util.Scanner;publicclassSum{publicstaticvoidmain(String[]args){Scanners=newScanner(System

publicstaticvoidprintNum(intn){for(inti=2;ij){if(i%j==0){m++;}}else{break;}}if(m<1){System.out.print

importjava.util.Arrays;importjava.util.Scanner;publicclassDataCompare{\x09publicstaticvoidmain(Strin

m1和m2就是要找的那两个数这里认为规定了m1

步长改为2,就是n+=2；偶数一定不是素数.还有,被检验的数不是素数的话肯定能被之前的素数整除.所以用之前的检测出的素数除被检测书就行了,然后判断一个素数之需除到它的一半就行了.我只是为了运行速度提出

#include#includeintisprime(intn){intt,i;t=(int)sqrt(n);for(i=2;i

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){Scannerin=newScanner(Syst

packagea1;importjava.util.Scanner;publicclassTest1{publicstaticfloatzhouchang(floatx,floaty){return2

importjava.util.Scanner;publicclassCircle{    publicstaticvoidmain(String[]args)

Scannerscanner=newScanner（system.in)intx,y,z,temp;System.out.println("请输入x:");x=scanner.nextInt();Sy

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){System.out.print("请输入第一个整

判断从键盘输入的三个数能否构成三角形.如果是特殊的三角形（如等边、等腰、直角,等腰直角）需要能判断出来.

importjava.util.Scanner;publicclassTest01{publicstaticvoidmain(String[]args){Scannerscan=newScanner(

publicclassJs{privatedoublea;privatedoubleb;privatedoublec;Js(doublea,doubleb,doublec){this.a=a;this

classOddSum//定义类{publicstaticvoidmain(Stringargs[])//main方法{intsum=0;//定义一个整形变量for(inti=1;i

importjavax.swing.JOptionPane;publicclassyuan{publicstaticvoidmain(Stringargs[]){doublep,s,l,r;Strin

哥们怎么又是你来?再问：您会不会的啊再答：packagetestt;importjava.util.Scanner;publicclassTest{\x09publicstaticvoidmain(S