用VB输入一个5位以内的整数,将其各位数字顺序反转输出.

Text1.text用于输入正整数Label1.Caption存放各位数字之和的计算结果计算事件Command1_ClickPrivateSubCommand1_Click()DimvalueAsLo

main(){longinta;intb,c,d,e,f;scanf("%ld",&a);while(a>=1&&a=1&&a/10000=1&&a/1000=1&&a/100=1&&a/10=1&&

被5整除的数有一个特点,分为两类,一类是可以被10整除,如10,20……,另一类就是不能被10整除但是能被5整除,如5,15……dimcount1aslong‘先看n整除以10等于多少,比如n是10的

创建两个text控件和一个command按钮控件再输入以下代码PrivateSubCommand1_Click()Fori=1ToLen(Text1.Text)a=Mid(Text1.Text,i,1

a=InputBox("请输入a")b=InputBox("请输入b")c=InputBox("请输入c")Ifat=aa=bb=tEndIfIfat=aa=cc=tEndIfIfbt=bb=cc=t

#include#includeintlen1,len2;chars1[905];chars2[905];intre[905];voidsub(){inti=0;intj;while(1){if(s1

http://zhidao.baidu.com/link?url=wyic3NEB45i2K9YZE2SpNiAV4aD7rZHpluBlyF76zg0n_8wr1t6-KOYm6eYY23KqG5n

不是已经有人问过了吗?这里：根据3512174的顺序自己敲一下代码就是了.

PrivateSubCommandButton1_Click()DimnNumAsLongIfIsNumeric(TextBox1.Text)ThennNum=Val(TextBox1.Text)If

#includeintchange(int);voidmain(){intc,d;cout

Private Sub Command1_Click()Dim i As Integer, j As Integer,&

PrivateSubCommand1_Click()Dima,b,cAsIntegerDimmaxRandomizea=Int(900*Rnd+100)b=Int(900*Rnd+100)c=Int(

#includemain(){inta,b;scanf("%d",&a);for(;a>=1;){b=a%10;printf("%d",b);a/=10;}printf("\n");}

namespaceConsoleApplication2{classProgram{staticvoidMain(string[]args){stringinput=Console.ReadLine(

PrivateSubCommand1_Click()d=Val(Text1)Print100*(dMod100)+Int(d/100)EndSu

=SUMPRODUCT(--(MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1)))

呵呵,一看就知道你刚学.我按照你的思路写的代码,你看看PrivateSubCommand1_Click()a=Val(Text1.Text)IfaText2="负整数"ElseIfa>0ThenTex

ifxmod2=0thenmsgbox"是偶数"elsemsgbox"是奇数"

longintn=123456789;inti=0;while(n>0){n=n/10;i++;}printf("整数长度为：%d",i);

Functionisprime(xAsInteger)DimkAsInteger,flagAsBooleank=2flag=TrueWhilek