求整数的3次方 c语言

程序如下：#include#includevoidmain(){inti,n,sum=0;scanf("%d",&n);for(i=1;i{sum+=pow(i,i);}printf("%d",sum

#include"stdio.h"intgys(intm,intn){if(n>1){if(m%n!=0){returngys(n,m%n);}elsereturnn;}}intmain(){intm

根据提示做是没问题的.先定义数组：intA[50];在提示基础上略加修改：inti=0,sum=0;floatavg;for(;scanf("%d",&A[i])==1&&i

已通过测试,#includevoidinput(intb[],intn);intf(inta[],intn);main(){inta[20],n,d;scanf("%d",&n);input(a,n)

#include#includeintmain(){intm,n,i,j,s;intarr[30][30];while(scanf("%d%d",&m,&n)!=EOF){for(i=0

#include#include#defineMaxline300voidmain(){voidmul(charstr1[],charstr2[]);charstr1[Maxline],str2[Ma

#includeintgongyue(intm,intn){intr;if(m==n)returnm;elsewhile((r=m%n)!=0){m=n;n=r;}returnn;}voidmain(

主函数第一行inty,intz少个逗号max函数第一行,也是这个错误,最后max函数return(n)改为returnn;

#includeintmain(){inti,n,sum;printf("请输入整数n:\n");scanf("%d",&n);for(i=1,sum=n;i{printf("%d的%d次方等于%d\

#includemain(){inta,b;scanf("%d%d",&a,&b);printf("最大数为%d\n",a>b?a:b);}

程序经过我用多组数据验证无错误,#includeintdigui(intt,intsum)//递归函数{if(t

太简单了吧#includevoidmain(){intA,bai,shi,ge;printf("请输入一个三位整数A：");scanf("%d",&A);bai=A/100;shi=A%100/10;

#include"stdio.h"main(){intx,n,i;longs=1;printf("pleaseinputxandn:");scanf("%d%d",&x,&n);for(i=1;i

#includeintcacl(intm){intsum=0,temp=m;while(m>0){temp=m%10;sum+=temp*temp*temp;m/=10;}returnsum;}int

6000=6*1000=2*3*5*5*40=2*3*5*5*5*2*2*2所以a=4,b=3,c=1(a-b-c)的2008次方=(4-3-1)的2008次方=0再问：谢谢！！

#includevoidmain(){intmax(intx,inty,intz);inta,b,c;scanf("%d%d%d",&a,&b,&c);intd=max(a,b,c);//没有定义加个

#include#includeintmain(intargc,char*argv[]){intn,i,j,s=0,z=0,d=1;longintm,max=1,min=1,left;scanf("%

#includeintmain(){\x09inti,sum,n=1;\x09while(1)\x09{\x09\x09sum=0;\x09\x09for(i=1;i10000)break;\x09\

#include#include#includeintmain(){intN=-1,NRev,k,found;charstrN[5];while(N!=0){printf("InputN(1000-9

#includevoidmain(){doubles=1.0;inti,N；scanf("%d",&N);for(i=0;i