C语言随机产生六位数密码
来源:学生作业帮助网 编辑:作业帮 时间:2024/04/28 12:12:50
#include#includevoidRAND_RECTANGE(intx);intmain(void){intx;srand(time(0));x=rand()%10;RAND_RECTANGE(
=TEXT(INT(RAND()*10^6),REPT("0",6))公式确保了生成的数据是六位,如果生成的随机数少于6位,前面能补足0
#include#include#includemain(){intm,n,M,N;m=rand()%10000+1;srand(time(NULL));n=rand()%10000+1;M=m%10
#include#include#includeusingnamespacestd;intmain(){intha=0;inthb=0;intn;cin>>n;srand((int)time(0));
#include#include#include#includeintmain(){\x05\x05charr[7];\x05inti,j,k,t,f;\x05srand(time(0));\x05f
#include#include#include#defineN10//随机出10道题目intmain(){\x09intnum1,num2,num3,count=0,result,resultTru
思路:分别产生个、十、百位上的随机数,依次组合在一起#include#include#includeintmain(){inti,tmp;num=0;srand((unsigned)time(NULL
#include#include#include#includevoidsushu(int*a);intmain(){inta[50],i;intt=200,d=500;srand(time(NULL
下个`里面有专破密码的
#include#include#include#include#include"windows.h"boolisprimer(intn){inti,sr=(int)sqrt(n)+1;for(i=2
20-90共有71个数字x=rand()%71+20;rand()%71产生0-70的随机数字
如果是不重复,即六个数各不相同,则有10*9*8*7*6*5=151200种如果可以重复则有10^6种
#include <stdio.h>#include <stdlib.h>#include <time.h>int mks(
#include#include#includemain(){srand(time(0));inta=rand()%900000+100000;printf("随机数%d",a);}
#include#include#include#defineN1000intfun(inta[],intnum);voidmain(){inti,a[N],b,num,n;printf("\n请输入
就是这个!刚刚出了点小错,现在可以了……楼主要解释可以追问#include#include#includemain(){charc;srand(time(0));c=rand()%3+65;print
#include#include#includeintmain(){inta,b,c;srand((unsigned)time(0));a=rand()%100+1;b=rand()%100+1;c=
三位的:srand((unsigned)time(0));chars[100];while(true){sprintf(s,"%d",rand()%1000);if(strlen(s)==3)brea
产生100为模的两个数字,记录下来;生成一个以4为模的数字,1对应+,2对应-.计算.#include<stdio.h>#include <time.h>void&n
//---------------------------------------------------------------------------#include<stdio.h>