C语言输出以星号的字母A

#include#includeintmain(){charc;printf("清输入一个英文大写字母：");scanf("%c",&c);chard=c-'A'+'a';printf("%c",d)

intmain(){intcountA_Z[26];intcounta_z[26];charc;inti;for(i=0;i='a'&&c='A'&&c

#includevoidmain(){inti,j;for(i=0;i

#includeintmain(){intn=5;inti;for(i=0;i

#include<stdio.h>int main(int argc, char* argv[]){ char ch; 

charch;scanf("%c",&ch);printf("%c\n",ch+1);

#includeintmain(){intcount[26]={0},i;charc;while((c=getchar())!='\n')if(c>='a'&&c再问：#includeintmain(

#includeintmain(){intn,i;scanf("%d",&n);//输入数字for(i=0;i

通过上面你的解释,我好像懂了点,但是,对应关系你要给出来啊,如果输入A,那么代表实际是?你要把这些对应关系给出了啊!这个貌似没啥难度》.再问：随便什么对应关系都行，谢谢。。。。再答：#include"

#includeintmain(){intx,y;while(scanf("%d%d",&x,&y)==2&&(x!=0||y!=0)){\x09printf("%d\n",x+y);}return0

#include#include#defineMAX_LENGTH20intmain(intargc,char*argv[]){intnlen=0;charwords[MAX_LENGTH]={};s

/*第一题*/#include#include#defineSCREEN_COLS80/*howmanycolumnsdoesterminalhave*/#defineHORIZONTAL_DISTA

我按照思路写了一遍,#incldue#include/*定义最多的“*”的个数*/#defineMAX4voidui_print_picture(void){inti=0;/*i记录当前的行数,最初时

#includemain(){chara;printf("inputachar:");scanf("%c",&a);if((a+5)>'z')printf("overflow\n");elseif((

#include<stdio.h>int main(){int i,j;for(i=1;i<8;i+=2){for(j=1;j<=i;j++)

#includeintmain(void){charch;printf("Pleaseinputacharacter:");ch=getchar();if((ch>='a'&&ch='A'))putc

#include"stdio.h"voidmain(){charch;scanf("%c",&ch);if(ch>='0'&&ch='a'&&ch='A'&&ch

****!输出菱形CLEARFORi=1TO4FORj=iTO3?""ENDFORFORj=1TO2*i-1?"*"ENDFORFORj=iTO3?""ENDFOR?ENDFORFORi=3TO1ST

优化了你的程序,你理解一下#includeintmain(){intn,i,j;scanf("%d",&n);//for(i=0;i

#includevoidmain(){\x09charc;\x09intcount=0;\x09while(c=getchar())//输入字符串,但每次只接收一个字符\x09{\x09\x09if(