C语言输入一个三位数,输出他们的个位数,十位数,百位数.
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intmain(intargc,char*argv[]){intinput;intret,num;printf("Inputaint:");scanf("%d",&input);for(;;){num
#includeintmain(void){inta;intge,shi,bai;scanf("%d",&a);ge=a%10;shi=a/10%10;bai=a/100;printf("%d\n",
#includevoidmain(){intx,a,b,c;scanf("%d",&x);a=x/100;b=x/10%10;c=x%10;x=c*100+b*10+a;printf("%d",x);
#includeintmain(){intn;scanf("%d",&n);do{printf("%d",n%10);}while(n/=10);printf("\n");return0;}
#includemain(){intn,i,j;scanf("%d",&n);n=2*n-1;for(i=1;i2*i){for(j=1;j
int类型所能容纳的数字位数不能超过10.我写的这个程序稍微长了点,但不受int类型容量的限制,能够处理很长的整数输入(由buffer数组的大小决定).这程序只处理纯整数输入.有疑问尽管问. 
swap(int&i,int&j){inttemp;temp=i;i=j;j=temp;}main(){inta,b,cscanf("%d,%d,%d",a,b,c);if(a
#includevoidmain(){inta,b,c,d;scanf("%d",&a);b=a/100;c=(a%100)/10;d=a%10;printf("%d",100*d+10*c+b);}
charch;scanf("%c",&ch);printf("%c\n",ch+1);
#include#includeintmain(){inti,num,n,ans,tt;while(scanf("%d",&num)!=EOF){ans=0;n=3;//如果要求N位数反转,把n改了就
#includevoidmain(){intn,m,a,b,c;scanf("%d",&n);a=n/100;b=(n/10)%10;c=n%10;m=c*100+b*10+a;printf("输出:
方法很多嘛随便来一个:#include#includevoidmain(){charp[10];char*q;inti=0;scanf("%s",p);q=p;while(*(q++))i++;q--
#includevoidmain(){inta;printf("请输入一个三位数:");scanf("%d",&a);printf("各位数上的乘积为:%d\n",(a/100)*(a%10)*(a/
#include <stdio.h>int main(void){ int num, i,
只是三位数的话,下面的代码就可以了!#includeintmain(){intn;inta,b,c;scanf("%d",&n);a=n%10;b=n/10%10;c=n/100;printf("%d
#includevoidmain(){inta;intb,c,d;//各个位数上的数字printf("请输入一个三位数:");scanf("%d",&a);b=a/100;//百位c=(a-b*100
#includeintmain(){inta[3];inti;for(i=0;i{scanf("%.1d",&a[i]);}printf("%d\n",a[0]+a[1]+a[2]);return0;
#includemain(){inti,j,N,t,k=0;intscore[100];printf("请输入整数的个数N:\n");scanf("%d",&N);printf("请输入N个整数:\n
#includeintmain(){floatF,c;while(1){printf("请输入华氏温度:");scanf("%f",&F);c=5*(F-32)/9;printf("摄氏温度为:%0.
inti,a,n;int*pl=NULL;printf("inputn:");scanf("%d",&n);if(n>0){pl=(int*)malloc(n*sizeof(int));}for(i=