c语言计算两个自然数数之间的和
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#include<stdio.h>#define ROW 3//行数#define COL 4//列数void PlusMatrix(in
#includevoidmain(){inta,b;printf("Inputtwointegers:");scanf("%d%d",&a,&b);printf("和:a+b=%d\n",a+b);p
//#includevoidmain(){intm,n,i,min,max;printf("Pleaseinputm,n:\n");scanf("%d%d",&m,&n);min=mn?m:n;if(
//别说100位,1000位都没问题,给你个例子.#include#definePRECISION2800#defineFRACTION1000#defineGROUP4#defineINITIALV
#include"stdio.h"intmain(){inta[10][10]={0};intn,i,j,sum1=0,sum2=0;scanf("%d",&n);for(i=0;i
#include<stdio.h>double zc(double x, double y){ ret
(8450-5050)÷100=3434+1=35
#includevoidmain(){intm,n,i,j,k;intsum=0;scanf("%d%d",&m,&n);for(i=m;i
运行结果是对的!问题估计错在输入语句的格式上,scanf("%d%d",&a,&b); 两个变量之间没有逗号,那么:从键盘上输入a=1,b=100应该是:
http://tieba.baidu.com/p/256969892
//先求3到100间的所有素数,存在数组中;//求该数组的所有为素数的元素之和,然后开方求平方根#include#includeintsushu[98];//开辟个最大容量的,假设都是素数/*从2开始
//---------------------------------------------------------------------------#includeintmain(void){i
#include#includeintmain(void){intn,m,i,j,t;scanf("%d%d",&n,&m);i=m>n?m:n;j=m>n?n:m;while(j){t=i%j;i=
不对,除了1和100..2和99,100.3和98,99,100.49和52,53,...100.的1+2+3+...+49=1225种.还有50和51,52,...100.51和52,53,...1
#includemain(){floata,b,s;printf("pleaceinputa,b:\n");scanf("%f%f\n",&a,&b);s=a+b;printf("%f\n",s);/
根据分析可得,25=13+12,所以,13×12=156,故答案为:156.
第一个题主要是判断闰年的问题.感觉有点烦,完了回去再写吧.第二个题简单,从后往前递推计算,第10天 吃之前 有 1 个第 9 天
#includeintmain(intargc,char*argv[]){intm,n;inti;intsum;printf("Pleaseinputmandn:\n");scanf("%d%d",&
#include "stdio.h"int main(){ int a,b,c,d,e; &n
代码如下:#includeintmon[12]={31,28,31,30,31,30,31,31,30,31,30,31};/*储存12个月的天数*/voidmain(){intspec_year(i