c语言编程求解P=1! 2! 3! -- 10!-搜答案-拍题作业网

#include<stdio.h>#include<stdlib.h>#include<time.h>int main(){ &nb

p是一个int指针吧?比如它指向的地址是8888,一个int占4字节那p-1就是8884,p-2就是8880就是从8876开始,内存的值为000000030000000200000001（不考虑高低位

、注意,数据别溢出.long是4个字节,double是8个字节.（Windows,VC6.0).2、你的程序：printf("1!+2!+.+20!=%ld\n",t);,最后也应该输出s.但是结果也

#includeintmain(){inti,n=1,sum=0;for(i=1;i

#include<stdio.h>void main(){ int sum=0,t=1,i; &nb

你自己写点,有问题我帮你调试.这个不难再问：不会写啊再答：编程就是个熟练活儿，多练习就会了# include <stdio.h>int main(void){

s=0sum=1;for(i=1;i

#inclludemain(){inta[]={3,1,5,9,6,2};inti.j,max,sum=0;max=a[0];for(i=0;imax)max=a[i];sum+=a[i];}prin

#includevoidmain(){inti,sum;for(i=1,sum=0;i

#includevoidmain(){longt=1,s=0;intn;for(n=1;n

#includeintmain(){inti,sum=0;for(i=1;i

#includeintisprime(intk){inti;for(i=2;i*i

#include//#includevoidmain(){intx,y,z;for(x=0;x

用个for循环就好了#includemain{inti=1,s;for(;i

main()intm[2][3]={1,2,3,4,5,6};for(inti=0;i

这是我们以前做过的课后习题...#includevoidmain(){intn,i;floats=0,t=1;scanf("%d",&n);for(i=1;i

include<stdio.h>void main(){ int maxsum=0; int sum; int pos

#include <stdio.h>void fun( int n ) //要传参数!{\x09int i;\x09d

1#include#includevoidmain(){printf("输入二次项系数、一次项系数和常数项：");scanf("%f%f%f",a,b,c);floatd=b*b-4*a*c;

#include"stdio.h"voidmain(){inta,b,c,d;c=(a=3*5,a*4);d=(b=3*5,b*4,b+5);printf("a=%db=%dc=%dd=%d\n",a