c语言编程从键盘输入若干数,用-1作为输入结束的标志

voidmain(){inta[10];intmax=0;inti;for(i=1;ia[max])max=i;}if(max!=0){i=a[0];a[0]=a[max];a[max]=i;}/*最

代码如下：#includevoidmain(){floata,b,c,d,max;printf("请输入四位数字：\n");scanf("%f%f%f%f",&a,&b,&c,&d);max=a;if

longsum;sum=0;inta,tmp;a=1;tmp=a;for(inti=0;i

什么报错?再问：就只有这个Cpp12.obj-1error(s),0warning(s)再答：你看下那个错误具体是什么，写一下。再问：--------------------Configuration

#includemain(){inti,x,n,s1=0,s2=0,s3=0;scanf("%d",&n);for(i=0;i

#includevoidmain(){inta[10];floataver=0;for(inti=0;i

改好了.#include#includefloatsum(floatx[8]);//你处理的是一个数组,不是一个数,而且声明函数的时候参数一定要加上类型,声明的时候要加一个分别结束floatave(f

#include"stdio.h"//voidmain(void){inta,b,c;printf("请输入两个十进制整数!\na=");scanf("%d",&a);printf("b=")

#includeintmain(){inta,b,c;charch;printf("请输入：");scanf("%d%c%d",&a,&ch,&b);if(ch=='+')c=a+b;elseif(c

#include#include#includeintmain(){inti,a[200]={0};charc;for(i=0;;i++){scanf("%c",&c);if(c=='\n')brea

#includeintmax(intn);voidmain(){inta,b;printf("Pleaseinputnumber,endof-1:");scanf("%d",&a);while(a!=

#includevoidmain(){\x09inta;\x09scanf("%d",&a);\x09printf("%d*%d=%d\n",a,a,a*a);}//运行情况：33*3=9请按任意键继

#includeintmain(){inta,b,c;intmin,max;scanf("%d%d%d",&a,&b,&c);if(amax)max=c;printf("%d%d%d",max,a+b

#includeintmain(void){intcount=0,n,sum=0;whlie(scanf("%d",&n)!=EOF){if(n==-1)break;elsesum+=n;count+

inta,sum,count;doubleavg;sum=0;count=0;while(1){printf("请输入正整数（输入0结束输入）:");scanf("%d",&a);if(a==0){b

#includevoidmain(){inti,j,n;printf("请输入n的值：\n");scanf_s("%d",&n);for(i=1;i

#includevoidmain(){intn,i,j,k,m;floats=0,t;i=1,j=2;printf("输入n:");scanf("%d",&n);for(m=1;m

#includeintk;voidshow(){chara;printf("Pleaseinputtheletter.\n");scanf("\n%c",&a);printf("Theletter's

intmain(){intn=0;inti=0;intsum=0;scanf("%d",&n);for(i=2;i

其实这种逻辑运算的,提现不错Java的面向对象的概念的,你直接写逻辑语句就好,首先判断等边,即if(a==b==c)System.out.print("该三角形是等边三角形");这样写下去就好了.希望