C语言求一个三位数的各位数字:当n为152时,分别求出n的个位数,十位数,百位数

#includeintmain(){intn,sum1,sum2,one;printf("inputn:");scanf("%d",&n);sum1=sum2=0;while(n)//当n不为0时循环

intmain(){\x09intnum=456;\x09intg,s,b;\x09g=num%10;//个位\x09s=num%100/10;//十位\x09b=num/100;//百位\x09pr

#includevoidmain(){inta,b,c;//a为百位,b为十位,c为个位intL;scanf("%d%d%d",&a,&b,&c);L=a*100+b*10+c;printf("%d"

#include "stdio.h"void main(){  int n,sum=0;  printf(&q

inti;inthh,mm,ss;intnum;for(i=100;i

#includeintmain(){intx;inta[20];scanf("%d",&x);inti;for(i=0;x>=10;i++){a[i]=x%10;x=x/10;}

这个算出来了#includeintmain(){inti,j,k,m,n;for(i=1;i

这个问题叫水仙花数吧代码是：#include#includeintmain(){intx,y,z,i;for(i=100;i

17*(a+b+c)=100a+10b+c83a=7b+16ca=1,b=5,c=3153

if(i=jiech(a)+jiech(b)+jiech(c))改成if(i==jiech(a)+jiech(b)+jiech(c))结果如下#includemain(){intjiech(intk)

#include"stdio.h"#include"conio.h"main(){inti;for(i=100;i

#includevoidmain(){inta,b,c,d;scanf("%d",&a);b=a/100;c=(a%100)/10;d=a%10;printf("%d",100*d+10*c+b);}

#include#includeintmain(){inti,num,n,ans,tt;while(scanf("%d",&num)!=EOF){ans=0;n=3;//如果要求N位数反转,把n改了就

这是求n个数的全排列：#includeints[21]={0};intn=0;voidswap(inta,intb){intt;t=s[a];s[a]=s[b];s[b]=t;}voidfp(

#includevoidmain(){inta;printf("请输入一个三位数：");scanf("%d",&a);printf("各位数上的乘积为：%d\n",(a/100)*(a%10)*(a/

#includevoidmain(){inti,j,k;for(i=1;i

#includeintmain(){intn,sum=0;printf("请输入一个整数：");scanf("%d",&n);while(n){sum=sum+n%10;n/=10;}printf("

ool func(int n){    int a = n/100;   &nb

#includeintmain(){inta[3];inti;for(i=0;i｛scanf("%.1d",&a[i]);｝printf("%d\n",a[0]+a[1]+a[2]);return0;

学到循环也能看懂#include<stdio.h>int main(){\x09int n,s=1;\x09scanf("%d",&n);\