C语言多于位个数直接输出吗

#includevoidmain(){intx,a,b,c;scanf("%d",&x);a=x/100;b=x/10%10;c=x%10;x=c*100+b*10+a;printf("%d",x);

#includeintmain(){\x09inta,b,c,d;printf("请输入三个数：");\x09scanf("%d,%d,%d",&a,&b,&c);\x09if(b>a)\x09{d=

我的思路是a>b1,若成立（1）b>c则输出a2,若不成立（1）假如b>c①成立则输出b②不成立输出c你可以按我的思路看看我的代码吗我只想知道我的代码哪儿错了程序如下：#includevoidmain

#includeintprime(intn){inti;for(i=2;i=n)return1;elsereturn0;}voidmain(){inti,k=0;for(i=7;i

printf("%.3f",变量)；试试看,貌似是这样……

#include#defineSIZE5*5intmain(){\x09inta[SIZE],i;\x09for(i=0;i

#include#includevoidmian(){intnum,i,temp[5];printf("请输入一个低于5位的整数\n");scanf("%d",&num);for(i=0;i

#includeintmain(void){longintx;inty,i=1;printf("请输入一个不超过100000的整数:");//99999||x

这个简单易懂#include#includevoidmain(){longintx;intg,s,b,q,w;intn;printf("\nInput(0~99999):");scanf("%ld",

#includeintmain(){inta[100];//定义a来存放数组inti,n,k=0,f;printf("请输入数组的个数：");scanf("%d",&n);printf("请输入数组的

#include#includeintmain(){longintnum;intindiv,ten,hundred,thousand,ten_thousand,place;printf("intput

#include#includeintn,num;voidcount1();voiddisplay1();voiddisplay2();voidcount2();intmain(){printf("

#include"stdio.h"intmain(intargc,_TCHAR*argv[]){inta=0;intb=0;printf("请输入数值");scanf("%d%d",&a,&b);pr

#includevoidmain(){floata,b,c,d,sum,average;printf("请依次输入4个实数,以空格间隔,以回车键结束:\n");scanf("%f%f%f%f",&a,

#includevoidmain(){inti,b=0;floatp,a[5],sum;for(i=0;i

#include"stdio.h"voidmain(){intx,a,b,c,d,e,n,j;printf("请输入一个不多于5位的正整数\n");scanf("%d",&x);a=x/10000;b

#include#defineMAXN20intmain(){intn,t,k=0;intia[MAXN];printf("请输入一个整数:");scanf("%d",&n);while(t=n%10

例程如下：#includemain(){inta[6]={1,2,3,4,5,6};inti;for(inti=0;i

#include#includeintmain(void){\x09intnum;\x09do\x09{\x09\x09printf("请输入一个不大于四位的数据:\n");\x09\x09scanf

#includevoidmain(){intn,i,m,t,a[100];for(n=1;n