方程x的平方-9x 18-搜答案-拍题作业网

2(x+3)^2×3(x+3)^2=36(x-2)^26(x+3)^2=36(x-2)^2(x+3)^2=6(x-2)^2x^2+6x+9=6(x^2-4x+4)x^2+6x+9=6x^2-24x+2

1.6a=7ba:b=7:62.3×45=15×93:15=9:453.3分之2x=0.75Yx:y=0.75:2/34.8X9=4X188:4=18:8

x(x^2-2)+2x^2(x+3)-3x(5x-7)=x(3x^2-9x+17)+2=>x^3-2x+2x^3+6x^2-15x^2+21x=3x^3-9x^2+17x+2=>2x=2x=1

2(x-3)²-(x+3)(x-3)=0(x-3)(2x-6-x-3)=0(x-3)(x-9)=0x=3,x=9

9(2x-1)^2-25(x+3)^2=0利用平方差公式[3(2x-1)-5(x+3)][3(2x-1)+5(x+3)]=0(x-18)(11x+12)=0x-18=0或11x+12=0x=18或x=

2005+2005的平方-2005x2006=2005x(1+2005-2006)=2005x0=058.4x1.4+18.6x58.4-20x18.4=58.4x(1.4+18.6)-20x18.4

1：（40/29-11/29）×18+92=1102：x=0,y=4；x=2,y=3；x=3,y=2；x=6,y=0就这些,负数你们用不到吧

9（2x-3）的平方=16（x+4）的平方9（2x-3）的平方-16（x+4）的平方=0[3(2x-3)+4(x+4)][3(2x-3)-4(x+4)]=0（10x+7）（2x-25）=010x+7=

4x^2+2x√(3x^2+x)+x-9=0,——》(4x^2+x-9)^2=4x^2*(3x^2+x),——》4x^4+4x^3-71x-18x+81=(x-1)(4x^3+8x^2-6x+81)=

x^2+9x^2/(x-3)^2=16,去分母,得x^2(x^2-6x+9)+9x^2=16(x^2-6x+9),x^4-6x^3+2x^2+96x-144=0,(x^2-8x+24)(x^2+2x-

9x²=(x-2)²3x=x-2,或者3x=2-x解得：x1=-1x2=1/2

9x的平方-169=0(3x+13)(3x-13)=03x+13=03x-13=0x1=-13/3x2=13/3

(x+1)²=9（x+1）²=3²x+1=±3x=-1±3x=2或x=-4

[2（x+1）十3（x-1）][2（x+1）-3（x-1）]=0x=1/5x=5

X=1啊

4（x-2)^2-9(2x+3)^2=0[2(x-2)+3(2x+3)][2(x-2)-3(2x+3)]=0(8x+5)(-4x-13)=0x1=-5/8,x2=-13/4

x的二次项的系数为0.m^2-9=0m=3(导致一次项系数也为0,舍去),m=-3(m+1)/2+(m-2)/3+1=-1-5/3+1=-5/3

9x^2=16(x+1)^216(x+1)^2-9x^2=0[4(x+1)]^2-(3x)^2=0[4(x+1)+3x]*[4(x+1)-3x]=0(7x+4)(x+4)=0x=-4,或x=-4/7

9x²=16(x+1)²(3x)²=(4(x+1))²3x=4x+1或3x=-4(x+1)x=-1,x=-4/7

X的平方+6X+9=0x²+6x+3²=0（x+3）²=0所以：x+3=0所以：x=-3