c#复数加减乘除计算符号的重载

classcomplex{intreal;intimg;public:complex(int_real,int_complex&operator+(complex&x){real+=x.real;}}

#includeusingnamespacestd;classCComplex{floatreal;floatimage;public:CComplexoperator+(CComplex&a)

//main函数里能输入两个复数.已经用VC++6.0编译通过了...希望对你有帮助#include#includeclassComplex{private:floatreal;floatimagin

classcomplex{public:complex(doubler=0,doublei=0){real=r;image=i;}doublereal;doubleimage;};complexope

#includeusingnamespacestd;classcomplex//复数类声明{public://外部接口complex(doubler=0.0,doublei=0.0){real=

usingSystem;namespacedoing{classdome{staticvoidMain(string[]args){doublea,b,c;Console.Wr

#include#includeclassComplex{public:Complex():_real(0),_imag(0){}explicitComplex(doubler):_real(r),_

新鲜出炉的,来吧.  class Program    {      

#includeusingnamespacestd;classComplex//定义complex类{public:Complex(){real=0;imag=0;}//定义构造函数Complex(d

#include<iostream>usingnamespacestd;classComplex{public: Complex(doubler=0,doublei=0):rea

#include#includeclassComplex{public:Complex(floata,floatb):m_real(a),m_imaginary(b){}Complex():m_rea

百度一下BCWHY去哪里提问吧.知道这里没人回答了.

#includeusingnamespacestd;classcomplex{public:complex():real(0),vir(0){}complex(floata,floatb):real(

一般有!=,!eques(""),sql里常用

x=a%b;z=a/b;前提是都是整型（int）的,不带小数点的再问：a/b不就是会有小数了么？如何取整数？再答：inta=37627;intb=60;x=a%b;z=a/b;定义成int型之后，就不

#includeusingnamespacestd;classComplex{floatReal,Image;public:Complex(floatr=0,floati=0){Real=r;Imag

// 以下实现供参考#include<stdlib.h>#include<stdio.h>class Matrix{   &n

写程序可以好好利用下网络,我在参考资料里面给你留下了搜索页面.在百度知道提问可能需要两天才能解决,但是用百度搜索半个小时就可以解决你的问题.网上的东西未必都是正确的,但是程序不会骗人,只要你的编译器通

usingSystem;usingSystem.Collections.Generic;usingSystem.Linq;usingSystem.Text;usingSystem.Reflection

 #include <iostream>#include<stdio.h>using namespace std;class