c 语言中,任意输入三位数
来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 20:46:51
#includemain(){inta=1,b=0,c=0,q;for(;a
定义四个变量intn,max,min,sum;先读一个数据scanf("%d",&n);sum=max=min=n;再循环9次,输入9个数,同时,累加,比较大小for(i=0;imax)max=n;i
#includeintmain(){intn;scanf("%d",&n);do{printf("%d",n%10);}while(n/=10);printf("\n");return0;}
#includeintmain(){intn;printf("请输入星期数:\n");scanf("%d",&n);switch(n){case1:printf("今天是星期一\n");break;c
#includevoidmain(){inta,b,c,d;scanf("%d",&a);b=a/100;c=(a%100)/10;d=a%10;printf("%d",100*d+10*c+b);}
#include#includeintmain(){inti,num,n,ans,tt;while(scanf("%d",&num)!=EOF){ans=0;n=3;//如果要求N位数反转,把n改了就
#includevoidmain(){intn,m,a,b,c;scanf("%d",&n);a=n/100;b=(n/10)%10;c=n%10;m=c*100+b*10+a;printf("输出:
一:#includevoidmain(){inti,j;inta[5][3];for(i=0;i
可以用sprintf(str,"%d",num);将数字输出为字符串,再用strlen(str)检查其长度:intnulen(intnum){charstr[10];sprintf(str,"%d",
楼主看这里#includevoidmain(){inti,j,num=0;for(i=0;i
#include <stdio.h>#include <stdlib.h> #include <time.h>&
#includeintmain(void){intn,m,j=0,k=0;printf("请输入一个数;\n");scanf("%d",&n);for(;n>0;){m=n%10;if(m%2==0)
#includevoidmain(){inta;printf("请输入一个三位数:");scanf("%d",&a);printf("各位数上的乘积为:%d\n",(a/100)*(a%10)*(a/
#include <stdio.h>int main(void){ int num, i,
先看是不是素数,是的话求余存起来,除以100存起来比较相等不相等的话输出
i==jk!=1&&k!=j
等同于C语言中的“\n”,即换行123即为123后换行
#includeintmain(){inta[3];inti;for(i=0;i{scanf("%.1d",&a[i]);}printf("%d\n",a[0]+a[1]+a[2]);return0;
#includevoidmain(){inta,b,num1,num2,temp;scanf("%d%d",&num1,&num2);if(num1
很简单等我马上好-----------------------以下是运行结果及源程序--------------------------------------001百位:0,十位:0,个位:1.Pr