把下列各式进行因式分解(1)x²-2x²y xy²-x

12.1）78²-22²=(78+22）*（78-22）=100*56=56002）1000²/（252²-248²）=1000²/【(25

1.原式=[2（x+y）+（x-y）][2（x+y）-（x-y）]=(3x-y)(x+3y)2.原式=9a^2b^4-6ab^2+1=(3ab^2-1)^23.原式=[(m/3)^2+n]^24.原式

（1）4a2 y2 -16a2 x2 =4a2（y2-4x2）=4a2（y+2x）（y-2x）；（2）2a2 x-2ax+12x=2x（a2-a+14

9a²-4（b+c）²=(3a+2b+2c)(3a-2b-2c)

D.x²＋4x＋4

4x²-x-1=4x²-x+1/16-17/16=(2x-1/4)²-17/16=(2x-1/4+√17/4)(2x-1/4-√17/4);很高兴为您解答,skyhunt

4xy²-4x²y-y³=-y（4x-4xy+y²）=-y（2x+y）²

1.x(x-y)^2-y(y-x)^2=(x-y)^2*(x-y)=(x-y)^32.18(a-b)^3-12b(b-a)^2=(a-b)^2*(18a-18b-12b)=6(a-b)^2*(3a-5

1.用平方差公式:(z²-x²-y²)²-4x²y²=[(z²-x²-y²)-2xy][(z²-x&

(1).1.(x+18)^2=(22+18)^2=16002.(2a-b)^2=(2*1/2-5/4)^2=1/16(2).(2x-3)^2=0x=3/2(3).xy(a-b)^2=5*6^2=180

(2m+3n)(2m-n)-4n(2m-n)=(2m-n)(2m+3n-4n)=(2m-n)(2m-n)=(2m-n)^2(x+y)^2(x-y)+(x+y)(y-x)^2=(x+y)(x-y)(x+

一.好像是x^2-y^2不然没法分解.x^2-y^2=(x+y)(x-y).二.(a+b)^2-100=(a+b)^2-10^2=(a+b+10)(a+b-10).三.1-a^2-b^2=-(a^2+

1、9a²-4b²=(3a)²-(2b)²=(3a+2b)(3a-2b)2、4x²-25y²=(2x)²-(5y)²=(

解题思路：因式分解解题过程：varSWOC={};SWOC.tip=false;try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/readq.ph

⒈－16分之1m³＋m.=-1/16m（m²-16）=-1/16m(m+4)(m-4)⒉x⁴－16.=(x²+4)(x²-4）=(x²+4

（1）原式=x(y^2+3y-10)-(y^2-4y+4)=x(y-2)(y+5)-(y-2)^2=(y-2)(xy+5x-y+2)（2）第二题观察一下,可以用(x+2)(x-4)与(x+3)(x-5

（1）（a²+1）（a+1）（a-1）（2）（3x-2）（3x-4）（3）（x+2）（x-2）（1-2x）（4）x（2y-3z）²（z+y）（z-y）

一解:(1)原式=(x-1)(7x-7+4)=(x-1)(7x-3)(2)原式=(a-b)(x-y)(3)原式=(p-3)(6m-4n)(4)原式=（y+2）（1-20y-40）=（y+2）（-20y

(1)x^3+3x^2+3x+9=x^2(x+3)+3(x+3)=(x^2+3)(x+3)(2)2x^2+xy-y^2-4x+5y-6=(2x-y)(x+y)-4x+5y-6=(2x-y)(x+y)+

30-11x-30x^2=-（30x²+11x-30）=-(5x+6)(6x-5)2(3x+1)^2-3(3x+1)(y-2)+(y-2)^2=[2(3x+1)-(y-2)][(3x+1)-