1.编写程序输出斐波那契数列的前20项,不使用数组来实现,要求每行输出5列.

functiona=fib(n)%生成长度为n的斐波那契数列ifn==1a=1;elseifn==2a=[11];elseb=fib(n-1);a=[b,b(end-1)+b(end)];end例子f

添加一个文本框输入前N项的N值,再添加一个命令按钮即可PrivateFunctionF(NAsLong)AsLongIfN>2ThenF=F(N-1)+F(N-2)ElseF=1EndIfEndFun

viewplaincopytoclipboardprint?publicclassFibonacci{/***@paramargs*/publicstaticvoidmain(String[]args

PrivateFunctionF(nAsLong)AsLongIfn>2ThenF=F(n-1)+F(n-2)ElseF=1EndIfEndFunctionPrivateSubCommand1_Cli

#includeintmain(){inti,j,n;printf("请输入一个整数:");scanf("%d",&n);for(i=0;ii;j--)printf("");for(j=1;j1)fo

#includevoidmain(){longa[42],i=2;a[0]=1;a[1]=1;for(;i

staticvoidMain(string[]args){doublei=1;doublej=1;doublen=1;while(true){Console.WriteLine("a{0}:a{1}=

publicclassFibonacci{publicstaticvoidmain(Stringargs[]){inti=1,j=1;for(intn=1;n

OptionExplicitDimFileNameAsString'文件名变量PrivateSubForm_Load()DimFilePathAsStringFilePath=App.PathIfRi

VB程序斐波那契数列代码ma,b,ciasintegera=1b=1fori=3to10c=aba=bb=cdebug.printcnexti

#include"stdio.h"intfun(intm){if(m==1){return1;}elseif(m==2){return1;}else{returnfun(m-1)+fun(m-2);}

#includeusingnamespacestd;intmain(){intf[11]={0,1,1};inti,j,n;for(i=3;i{f[i]=f[i-1]+f[i-2];i

#includevoidmain(){longf1=1,f2=1,i;for(i=0;i

#includeusingnamespacestd;#include/*编写程序,计算并输出下面数列前20项的和,结果取3位小数.(C++)2/1,3/2,4/3,5/4,6/5,7/6,8/7,……

#include"stdio.h"voidmain(){doublea,n,s=0;for(n=1;n

#include"stdafx.h"voidmain(){ints=0;for(intn=1;n

“i=1”---->"i==1","i=2"------>"i==2"

//#include"stdafx.h"//vc++6.0加上这一行.#include"stdio.h"voidmain(void){inta,b,f,i,n,m;printf("Typen&m(n

#include"stdio.h"intmain(){inti,n;inta=1,b=1,sum=0;scanf("%d",&n);if(n==0)printf("N=%d",sum);

用什么语言呢?C还是PASCAL、VB?再问：vc++再答：#include<stdio.h>main(){ longa[30],i; a[0]=1;a[1]=1;&n