怎样编程序 输入三个小数,输出最大的数

这个是我新编的,你可以试试#include#includevoidmain(){floata,b,c,d,s;scanf("%f,%f,%f",&a,&b,&c);if(a+b>c&&a+c>b&&b

a = 1;f = 1; lambda = 1;[xx, yy] = meshgrid(0:0.1:

scanf("%d,%d,%d,&a,&b,&c");改成scanf("%d,%d,%d“,&a,&b,&c);printf("thelargerstnumberis%d\n,max");改成prin

#include"stdio.h"intmain(){inta,b,c,tmp,max;printf("inputa,b,c:");scanf("%d%d%d",&a,&b,&c);if(a>b&&a

voidmain(){inta[10],min,max;cout

可以用sprintf(str,"%d",num);将数字输出为字符串,再用strlen(str)检查其长度：intnulen(intnum){charstr[10];sprintf(str,"%d",

任意两边和大于第三边任意两边差小于第三边A,B,C>0A+B>CA+C>BB+C>A|A-B|

#include"stdio.h"voidmain(){\x09inta;\x09intb[3];\x09intcount=0;\x09printf("请输入一个数");\x09scanf("%d",

#include<stdio.h>int main(){\x09int x,y;\x09printf("输入x的值："); \x09sca

华氏转摄氏公式：T℉=1.8t℃+32#includeintmain(){floatf,c;printf("输入华氏温度：\n");scanf("%f",&f);c=(f-32)/1.8;printf

#include#includeintmain(){doublea=1,b=1;doubles=0;inti,n;scanf("%d",&n);for(i=1;i

//#include"stdafx.h"//vc++6.0加上这一行.#include"stdio.h"voidmain(void){charn[20],*p=n,*pt;intm=0;printf(

#include//希望对您有用#includeintmain(){intx,y;printf("Pleaseenterthenumber:");scanf("%d",&x);if(x

#include"stdio.h"intmain(){intd[10],i,j,k,t[5];printf("输入十个整数：");k=0;//存储的序号（去重复）for(i=0;i

voidmain(){floatx,y;cin>>x;if(x=10)y=3*x-11;elsey=2*x-1;cout

#include <iostream>using namespace std;int main(){int a,b,c,t;cin&nbs

#include"math.h"#includevoidmain(){\x05inta;\x05floatp,q;\x05printf("inputa:");\x05scanf("%d",&a);\x

#includeintmain(void){charch;printf("Pleaseinputacharacter:");ch=getchar();if((ch>='a'&&ch='A'))putc

QBINPUTA,B,CMAX=AIFMAX

intA,B,CifA>BandB>Cthenmessagebox("排列”,A,B,C）elseifA>BandBCthenmessagebox("排列”,A,C,B）else...........