已知丨x-3丨 (3y 4)的平方等于零则xy等于几?
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原式分解因式得x^3y^3(2x-y)=(xy)^3(2x-y)=8/3.(x^3表示x的3次方)
4y4,y,4xy,3x²y,3x3次方
原式=(x4-xy3)+(y4-x3y)+(3xy2-3x2y)=x(x3-y3)+y(y3-x3)+3xy(y-x)=(x3-y3)(x-y)-3xy(x-y)=(x-y)(x3-y3-3xy)=(
∵x+y=6,xy=4,∴(1)x2+y2=(x+y)2-2xy,=62-2×4,=28;(2)(x-y)2=x2+y2-2xy,=28-2×4,=20;(3)x4+y4=(x2+y2)2-2x2y2
解(15x^4y^4-9x^5y³-3x^6y²)/(-3x²y)²=(15x^4y^4-9x^5y³-3x^6y²)/(3x²y
由(2)得4x=3y=6z,∴x=34y,z=12y;代入(1)得:y=4,代入(2)得:x=3,z=2,方程组的解为x=3y=4z=2.
按字母x的升幂排列就把y看成系数y4-xy3+x2y2+3x3y
(x+y+z)²-(x²+y²+z²)=2(xy+yz+zx)=-1,xy+yz+zx=-1/2x3+y3+z3=3xyz+(x+y+z)(x²+y&
(x+y+z)^2=[(x+y)+z]^2=(x^2+2xy+y^2)+z^2+2zx+2zy=x^2+y^2+z^2+2xy+2xz+2yz=x^2+y^2+z^2+2(xy+xz+yz)=0x+y
∵x+y=a∴x2+y2+2xy=a2又∵x2+y2=b2∴2xy=a2-b2x4+y4=(x2+y2)2-2x2y2=(x2+y2)2-(2xy)22=b4−(a2−b2)22=-12a4+a2b2
奇数项是正,偶数项是负.2004项是偶数项求和可以把两项当成一项即(x*x-2x*x)+.+(2003x*x-2004x*x)=-1002x*x也可分别求奇数和偶数项的和,再相减即可.当X=-1/2时
(x2+z2)(x2+y2)(y2+z2)=(x+y)2-2xy×(x+z)2-2xz×(y+z)2-2yz--之后不清楚了
1)2x³y—4x平方y平方+2xy³=2xy(x²-2xy+y²)=2xy(x-y)²2)x4次方—2x平方y平方+y4次方=(x²-y&
1/2x^a-1y4-b与多项式3x^3y+2x^2y^2的和是二项式当1/2x^a-1y^4-b与3x^3y是同类项时,a-1=3,4-b=1则,a=4,b=3a+b=4+3=7当1/2x^a-1y
D:他们的取值范围都是一样的y2中x不能等于零y1跟y3也是一样的可以去所有值y4中x不能是负数
y^2+3y-1=0把y=0代入-1=0,不成立所以y不等于0两边除以yy+3-1/y=0y-1/y=-3平方y^2-2+1/y^2=9y^2+1/y^2=11平方y^4+2+1/y^4=121y^4
根据题意得:x3−y4=33x+2y=78,整理得:4x−3y=36①3x+2y=78②,①×2+②×3得:17x=306,解得:x=18,将x=18代入①得:y=12,则方程组的解为x=18y=12
根据题意,得x+y2=3x−2yx+y2=10+6x+y4,整理得x−y=0(1)4x−y=−10(2),由(1)-(2),并解得x=-103(3).把(3)代入(1),解得y=-103,所以原方程组
x4-xy3-x3y-3x2y+3xy2+y4=(x4-xy3)+(y4-x3y)+(3xy2-3x2y)=x(x3-y3)+y(y3-x3)+3xy(y-x)=(x3-y3)(x-y)-3xy(x-
(x^4-y^4)÷(x^2+y^2)/(x+y)=(x^2-y^2)(x^2+y^2)÷(x^2+y^2)/(x+y)=(x^2-y^2)(x^2+y^2)*(x+y)/(x^2+y^2)=(x^2