已知Y X-X Y=5

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已知x2+y2-2x-4y+5=0,分式yx−xy

∵x2+y2-2x-4y+5=0,∴x2-2x+1+y2-4y+4=0,(x-1)2+(y-2)2=0,∴x=1,y=2,∴yx−xy=2-12=1.5;故答案为:1.5.

已知x+y=8,xy=6,求yx+xy

yx+xy=xyx+xyy=xy(x+y)xy,∵x+y=8,xy=6,∴原式=6×86=463.

已知x2+y2-6x-8y+25=0,求代数式yx−xy

∵x2+y2-6x-8y+25=0,∴(x-3)2+(y-4)2=0,∴x=3,y=4,当x=3,y=4时,原式=43-34=712.

已知:y=1−8x+8x−1+12,则代数式xy+yx+2-xy+yx−2的值为(  )

∵1-8x≥0,8x-1≥0,∴x=18,y=12,∴代数式xy+yx+2-xy+yx−2=14+4+2-14+4−2=52-32=1.故选:B.

已知3x2+xy-2y2=0,求(x+yx-y+4xyy

原式=[(x+y)2(x-y)(x+y)+-4xy(x-y)(x+y)]×(x+3y)(x-3y)(x+3y)(x-y)=x-3yx+y,由已知得(3x-2y)(x+y)=0,因为x+y≠0,所以3x

已知1x−1y=3,则5x+xy−5yx−xy−y的值为(  )

根据分式的基本性质,分子分母都除以xy得,5y+1−5x1y−1−1x=−3×5+1−3−1=72.故选B.

已知y=3xy+x,求代数式2x+3xy−2yx−2xy−y

因为y=3xy+x,所以x-y=-3xy,当x-y=-3xy时,2x+3xy−2yx−2xy−y=2(x−y)+3xy(x−y)−2xy=2(−3xy)+3xy−3xy−2xy=35.

已知x2-4xy+4y2=0,那么分式x-yx+y

∵x2-4xy+4y2=0,∴(x-2y)2=0,∴x=2y,∴x-yx+y=2y-y2y+y=13.故分式x-yx+y的值等于13.

xy+yx=10x,y是多少

xy+yx=10x+y+10y+x=11x+11y=100+x10x=100-11yx=10-1.1y所以y只能是0

已知x-y=4xy,则2x+3xy-2yx-2xy-y

∵x-y=4xy,∴2x+3xy-2yx-2xy-y=2(x-y)+3xyx-y-2xy=8xy+3xy4xy-2xy=112.故答案为:112.

xy=yx 有什么关系?

乘法交换律,所以相等

已知yx^2+2xy^3+3=-18 求dy/dx

两边对x求导得y'x^2+2xy+2y^3+4xy^2y'=0解出来y'就可以了再问:4xy^2y'为什么是4xy再答:搞错了,应该是6xy^2y'再问:yx^2+2xy^3+3=-18上点(1,-2

已知2x2-3xy+y2=0(xy≠0),则xy+yx的值是(  )

根据题意,2x2-3xy+y2=0,且xy≠0,故有(yx)2−3yx+2=0,即(yx−1)(yx−2)=0,即得yx=1或2,故xy=1或12,所以xy+yx=2或212.故选A.

已知x+y=2,xy=-5,则yx+xy

yx+xy=x2+y2xy=(x+y)2-2xyxy当x+y=2,xy=-5时,原式=22-2×(-5)-5=-145.故答案为-145.

已知2x2-xy-3y2=0,求x−yx+y

2x2-xy-3y2=0,(2x-3y)(x+y)=0,解得:2x-3y=0或x+y=0(分母为0,舍去),解得:x=3y2,则x−yx+y=3y2−y3y2+y=y5y=15.

已知2的X次方等于5的Y次方等于10的Z次方,求证:XY=XZ+YX

XY=XZ+YX?那么也就是XY=X(Z+Y)咯,Y=Z+Y?无法证明的.题抄错啦~`

已知xy满足x^2+y^2+4/5=2x+y 求代数式yx/x+y的值

你抄错题了吧X2+Y2+5/4=2X+Y移项,得(X-1)2+(Y-1/2)2=0X=1,Y=1/2

已知5x2-xy-6y2=0,则yx

∵5x2-xy-6y2=0,∴(5x-6y)(x+y)=0,∴5x-6y=0,x+y=0,∴5x=6y,x=-y,∴yx=56或-1.故答案为:56或-1.

xy*yx=2268

即(10x+y)*(10y+x)=2268101xy+10x²+10y²=2268因为后面的10x²+10y²只可能是整十的数,所以2268中的个位8要靠101