1. 编写函数文件,计算从1到n的阶乘的和,并求出当n=20时表达式的值.-搜答案-拍题作业网

cal.m文件如下：function y = cal(n) c = 1:n; &n

intsum(intn){inti=1;intsum_i=0;for(;i

第一个：v=0;num=0;whilenum

functionzanswer=cali(n)count=0;fori=0:ncount=count+2^i;endzanswer=count;不好意思,看错了,不知你的代码怎么敲的functionz

floatfun(intn){floatsum=0;inti;for(i=1;i

#!/bin/bashread-p"Enteranum:"numsum=0foriin$(seq$num)dosum=$((sum+i))doneecho"Sumis$sum"

#includelongfac(intn){inti;longx=1;for(i=2;i再问：谢谢咯！可是我说的是递归法哦！再答：#includelongfac(intn){if(n==0)retur

#includemain(){inti,j,n,k,t;doublesum=2;printf("inputanumber:\n");scanf("%d",&n);j=2;k=1;for(i=1;i再问

如果是要求前N个偶数之和：#includeusingnamespacestd;longFunctionadd(intn){longsum=0;for(inti=0;i

importjava.util.Scanner;publicclassOushu{Oushu(){try{System.out.println("请输入n值");Scannerin=newScanne

function [ s ] = solve_area( a,b,c ) p=(a+b+c)./2;&nbs

这个已经帮你做完了哈

Functionsum(n)AsDoublesum=0Fori=1TonIfiMod2=0Thensum=sum+i*iNextEndFunction

%编成M函数文件运行后,在命令窗口输入要知道的自然数n,即可求得对应项的Fibonacci数列%有哪步有疑问请问user_entry=input('Pleaseenterthenumberyouwan

sum=0;form=1:1000sum=sum+m;endsum

functionFibon(n)switchncase0disp('输入有错,请重新输入参数')case1disp('F(1)=')disp(n)case2disp('F(2)=')disp(n)ot

#includeusingnamespacestd;voidmain(){inta=0,b=0;cin>>a>>b;cout

#includevoidmain(){inta,b,sum=0;printf("请输入两个整数：");//将两个改成n个就好了scanf("%d%d",&a,&b);sum=a+b;printf("%

functionf=d(n)f(1)=1;f(2)=1;fori=3:nf(i)=f(i-1)+f(i-2);end

int main( ){ int s,e,i,n,A[100]; double m;&nbs