8x-3*9 37解方程
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x-3/4x=81/4x=8x=32
3x-[5-6(2-x)]=83x-[5-12+6x]=83x-5+12-6x=8-3x=8+5-12-3x=1x=-1/3
(x+3)/(x+2)+(x+9)/(x+8)=(x+5)/(x+4)+(x+7)/(x+6)1+(x+5)/(x+2)(x+8)=1+(x+5)/(x+4)(x+6)x=-5再问:第二步那个1是怎么
将x-7/x-9分解成1+2/(x-9)其他分式同理则原方程等价于1/x-9+1/x-5=1/x-6+1/x-81/x-6-1/x-5=1/x-9-1/x-81/(x-5)(x-6)=1/(x-8)(
移项8x-7x=3+3x=6再问:太给力了,你的回答完美解决了我的问题!
x(2x-4)+3x(x-1)=5x(x-3)+82x²-4x+3x²-3x=5x²-15x+88x=8x=1
3x+8=413x=41-83x=33x=33÷3x=11
3x+8(x-3)=1963x+8x-24=19611x=220x=20
令2x-11=0,得x=11/2令x-3=0,得x=3令x-8=0,得x=8当x
通分得[(x-8)(x-4)-(x-9)(x-3)]/(x-3)(x-4)=[(x+7)(x+3)-(x+2)(x+8)]/(x+8)(x+3)解得5/(x-3)(x-4)=5/(x+8)(x+3),
(x^2+x)(x^2+x-3)-3(x^2+x)+8=0(x^2+x)^2-6(x^2+x)+8=0(x^2+x-4)(x^2+x-2)=0x^2+x-4=0x^2+x-2=0(x+1/2)^2=1
(x+8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3)[(x-8)(x-4)-(x-9)(x-3)]/(x-3)(x-4)=[(x+7)(x+3)-(x+2)(
首先由题意得x+1≠0,x+7≠0,x+5≠0,x+3≠0,即x≠-1,x≠-7,x≠-5,x≠-3,则先简化方程(x+1+1)/(x+1)+(x+7+1)/(x+7)=(x+5+1)/(x+5)+(
(x-3)(x+8)=(x+4)(x-7)+2(x+5)x²+5x-24=x²-3x-28+2x+105x+3x-2x=24-28+106x=6x=1
用换元法设x*x+11x-8=A然后再做
去分母得:3x-6-2x=0,解得:x=6,经检验x=6是分式方程的解.
令X^2+X=YY(Y-3)-3Y+8=0Y^2-6Y+8=0(Y-2)(Y-4)=0y=2Y=4X^2+X=2x^2+x=4x^2+x-2=0x^2+x-4=0(x+2)(x-1)=0X=1/2(-
2x-7/8x=3/816/8x-7/8x=3/89/8x=3/8x=3/8*8/9x=1/3
3x+3x+24=846x+24=846x=60x=10