80(1-x)y= 3 20 ×80(100-y)

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{3(x+y)+3(y+x)=1,3(x+y)+4(y-x)=-1

3(x+y)+3(y-x)=1(1)3(x+y)+4(y-x)=-1(2)(2)-(1)得y-x=-2(3)代入(1)3(x+y)-6=1x+y=7/3=>x=7/3-y又由(3)得x=y+2y+2=

(1)x+y=420,30%x+40%y=160×80% (2)x-y/7-x+y/6=1/2,2(x-y)-5(x+y

(1)由原方程化简得x+y=420①,0.3x+0.4y=128②①-②×2.5得x-0.75x=420-3200.25x=100x=400把x=400代入①得y=20∴x=400,y=20(2)由原

解方程.100/(X+Y)+64/(X-Y)=9;80/(X+Y)+80/(X-Y)=9

把X+yX-y看成整体X+Y=20X-Y=16X=18Y=2

25^x=2000,80^y=2000,试说明1/x+1/y=1

∵25^x=2000∴(25^X)^Y=2000^y即25^xy=2000^y①∵80^y=2000∴(80^y)^x=2000^x即80^xy=2000^x②①*②得(25*80)^xy=2000^

若x-y=1,求代数式x(x-y)+y(y-x)+2013的值

因为X-Y=1所以原式=x*1+y*(-1)+2013=x-y+2013=1+2013=2014

x+80%y=42 y-x=12

x+80%y=42y-x=121.8y=54y=30x=18

(1) ,(1000+2X)/Y=120 (2),(1000-2X)/Y=80

(1000+2X)/Y=120(2),(1000-2X)/Y=80:所以1000+2x=120y,1000-2x=80y:两式相除得(1000+2X)/(1000-2X)=3/2:所以(1000+2X

已知25x=2000,80y=2000,则1x+1y

由已知得20001x=25,20001y=80,两式相乘,得20001x×20001y=25×80=2000,∴1x+1y=1.故答案为:1.

1.已知1/x+1/y=-1/x+y,则y/x+x/y=?

1.1/x+1/y=(x+y)/xy=-1/(x+y)去分母可得,(x+y)^2+xy=0即x^2+y^2=-3xy所以y/x+x/y=(x^2+y^2)/xy=-32.由1/x-1/y=5可得y-x

先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y

解(x-y)(x+y)-(x-2y)²+x(3x-5y)-(x-y)(x-2y)=(x²-y²)-(x²-4xy+4y²)+(3x²-5xy

{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1

3(x+y)-4(x-y)=4(x+y)/2+(x-y)/6=1令a=x+y,b=x-y3a-4b=4(1)a/2+b/6=1则3a+b=6(2)(2)-(1)5b=2b=2/5a=(6-b)/3=2

已知4x=9y求(1)x+y/y (2)y-x/2x

4x=9yx=9/4*y(1)(x+y)/y=[(9/4)y+y]/y=(9/4+1)y/y=9/4+1=13/4(2)(y-x)/2x=[y-(9/4)y]/[2*(9/4)y]=(1-9/4)y/

10.有如下选择结构:If x>90 then y=x elseIf x>80 then y=x-1 else y=1-

Ifx>90theny=xelseIfx>80theny=x-1elsey=1-xEndIf要让y=1-x,则只需最后一个选择成立即可.于是得出,x

已知25x=2000,80y=2000,则1x+1y等于(  )

由已知得20001x=25,20001y=80,两式相乘,得20001x+1y=25×80=2000,∴1x+1y=1.故选B.

Y-X=45 (80%Y-X)×8=(Y-35-X)×12

(80%Y-X)×8=(Y-35-X)×12化简得:2(0.8y-x)=3(y-x-35)1.6y-2x=3y-3x-105x-1.4y=-105-x+y=45两式相加得:-0.4y=-60y=150

用加减消元:x-y=80(1+20%)y-(1-25%)x=30

x-y=80①(1+20%)y-(1-25%)x=30②对②整理:1.2y-0.75x=30①×0.75+②-0.75y+1.2y=80×0.75+300.45y=90y=200代y=200入①x=8

y=[x-1],

取整

{4/(x+y)+6/(x-y)=3 {9/(x-y)-1/(x+y)=1

完整设1/(x+y)=a,1/(x-y)=b原方程组可变为4a+6b=39b-a=1a=9b-136b-4+6b=3b=1/6,a=1/2x+y=2x-y=6所以原方程组的解为:x=4,y=-2