定义函数fact 计算n的阶乘

#include"stdio.h"intfact1(intn){if(n==1||n==0)return1;elsereturnn*fact1(n-1);}intfact2(intn){inti,t=

#include <stdio.h>int main(void){     int n; &nbs

eturn是函数返回值语句,作用是返回调用该函数地方.在函数体内应该只有一个{if(n==1)return(1);elsereturnfact(n-1)*n;//计算n-1

#includeintfact(intn);usingnamespacestd;intmain(){intn;cin>>n;cout

#includeintfact(intn){if(n==1)return1;elsereturn(n*fact(n-1));}main(){intn;printf("inputanumber:

#include#includedoublefun(intn);intmain(){printf("Inputn:");intn;scanf("%d",&n);doubleS=fun(n);

intjie_cheng(intn){if(n==1)return1;returnn*jie_cheng(n-1);}doublefact(intn){doublesum=0;for(inti=1;i

你确定函数类型是要double?这个是整型的#includeintfact(int);voidmain(){intn;scanf("%d",&n);for(inti=1;i

inttotal(intn){returnfact(n);}intfact(intn){if(n==1)return1;elsereturnn+fact(n-1);}

intfun1(intn)//其实返回double型比较好,因为int型能表示的数太小了（对于阶乘来说）{intfac=1;//如果返回double型的话,这里不要忘记改for(inti=1;i

vars,ans:int64;i:longint;beginreadln(s);fori:=1tosdoinc(ans,facto(i));writeln(ans);end.也许需要高精度!当s>=1

longfact(intn){inta,i;a=1;for(i=2;i再问：如何调用这个函数呢再答：在主函数中调用，也可以在其他函数中。例如voidmain(){longlaw;law=fact(10

doublefact(intn){doubletemp;if(n==0||n==1)return1.0;if(n>=2){temp=double(n*fact(n-1));rentuntemp;}}

#includeintmain(){intn;doublem;doublefac(intn);scanf("%d",&n);m=fac(n);printf("%d!=%f\n",n,m);return

这是我用递归写的程序.#includeintfact(intn){if(n==0||n==1)return1;elsereturnn*fac(n-1);}intmain(){intm,n,sum;pr

publicinttotal(intn){intresult=0;for(inti=1;i

#includeusingnamespacestd;intfct(intn){intsum=0,x;if(n再问：Error:5_0_2136175_29393.cLIBC.lib(crt0.ob

OptionExplicitDimsAsIntegerPrivateSubCommand1_Click()Text2.Text=Str(fact(Val(Text1.Text)))s=0EndSubP

java版实现public class Calculator{    public int calTest(int&nb

intfun(intn){inti,jiech;jiech=1;for(i=1;i