完成下面程序:输入两个整数a和b,返回a除以b的余数.

#includevoidmain(){inta,b;printf("Inputtwointegers:");scanf("%d%d",&a,&b);printf("和:a+b=%d\n",a+b);p

//正确的程序如下：#includevoidmain(){inti,j,n,*tem[3];intp[2][3],q[3][2],r[2][2];tem[0]=p[0];tem[1]=q[0];tem

#includeintmain(){\x09inta,b;\x09scanf("%d%d",&a,&b);\x09printf("商为%.2f余数为%d\n",1.0*a/b,a%b);\x09ret

额,这个更简单了if(i%7==0)

#includeintmain(){inta,b;scanf("%d%d",&a,&b);printf("%d",a-b);return0;}

#include#incluedvoidmain(){inta;intb;intc,d;a=1500,b=350;c=a/b;//商数d=a%b;//余数pritf("商数为:%d\n",c);pri

#includeintmain(){inta,b,c,d=0;scanf("%d%d",&a,&b);c=a/b;d=a%b;printf("商是:%d\n",c);printf("余数是:%d\n"

#includevoidmain(){inta,b;printf("pleaseinputtwonums:");scanf("%d%d",&a,&b);printf("%d%d\n",a/b,a%b)

#includevoidmain(){inta1,a2;floate;scanf("%d%d",&a1,&a2);printf("%d+%d=%d\n",a1,a2,a1+a2);printf("%d

搜一下：欧几里德算法代码如下：intgcd(intx,inty){if(xif(y==0)returnx;returngcd(y,x%y);}最大公约数：gcd(x,y)最小公倍数：x*y/gcd(x

inta,b;scanf("%d%d",&a,&b);while(a{intt=a;a=b;b=t;}if(a%b==0)printf("a能被b整除");elsepr

printf()和scanf()都是C语言里的标准输出、输入函数哦.stdio、h什么的是程序运行时要调用的.我想,你也许不是要一个真的可以在电脑上跑的程序吧?如果单纯按数学意思来的话,MOD是取余算

vari,j,n,m:longint;procedureprint(c:char;a:integer);vari:longint;beginfori:=1toadowrite(c);end;begin

请问用什么语言编写?再问：我的失误！用C#

voidfun(inta,b)//应该是(int*a,int*b)吧{intt;//a=b;//这句误事,删掉就好b=t;//不用我说了吧}

1.main(){inta=560;printf("%d时%d分",a/60,a%60);}2.main(){inta,b,t;printf("请输入a：");scanf("%d",&a);print

下面这个程序,实现了分钟到日,小时,分钟的转换#include<stdio.h>#include<stdlib.h>intmain(){intday=0,hour,minute

算法程序：#includevoidmain(){inta,b;printf("inputa,b:(a>b)\n");scanf("%d,%d",&a,&b);if(a%b==0)printf("OK\

#includevoidmain(){inta,b,c;printf("请输入三个整数,以空格分隔：");scanf("%d%d%d",&a,&b,&c);inttemp;if(a>b){temp=a

#includeintGcd(intM,intN){intRem;while(N>0){Rem=M%N;M=N;N=Rem;}returnM;}voidmain(){inta,b