6xy²-9x²y-y³
来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 08:40:09
解题思路:提取公因式进行分解解题过程:附件最终答案:略
3xy是3x原式=(x-3y)(x+2y)+3x+y+2十字相乘x-3y2×x+2y1所以原式=(x-3y+2)(x+2y+1)
解题思路:本题主要利用完全平方公式进行因式分解即可求出结果解题过程:解:x²-6xy+9y²=(x-3y)2
Solution:x^2-2xy+3y^2=9(1)4x^2-5xy+6y^2=30(2)Eq(1)*5-Eq(2)*2,wehavex^2-y^2=5(3)Eq(2)-Eq(1),wegetx^2+
xy-1+x-y=XY+X-Y-1(加法交换律)=(XY+X)-(Y+1)=X(Y+1)-(Y+1)(提取公因式X)=(Y+1)(X-1)(提取公因式Y+1)这样可以么?
1、平方差原式=[(2x+3y)+(x+2y)][(2x+3y)-(x+2y)]=(2x+3y+x+2y)(2x+3y-x-2y)=(3x+5y)(x+y)2、3|x-3|+(x-3y)²=
解题思路:此题主要考查了利用完全平方公式分解因式,正确记忆完全平方公式是解题关键.解题过程:
解题思路:根据题意,由完全平方公式的知识可求解题过程:varSWOC={};SWOC.tip=false;try{SWOCX2.OpenFile("http://dayi.prcedu.com/inc
x^2-6xy+9y^2+x^2y-9y^3=(x-3y)^2+y(x^2-9y^2)=(x-3y)^2+y(x+3y)(x-3y)=(x-3y)(x-3y+xy+3y^2)
6x+6y=9x+4y3x-2y=0……1式6x+6y=xy……2式2式-1式乘以2得10y=xyx=10y=15请及时采纳
方是什么是平方吗再问:嗯再答:=x(2x-3)-3y(2x-3)=(2x-3)(x-3y)
√x^-2xy+y^2+x^2-6xy+9y^2/x-3y=√(x-y)^2+(x-3y)^2/x-3y由于y>x=y-x+x-3y=-2y=-2√5
原式=-y(9x²-6xy+y²)=-y(3x-y)²
[(x-y)/(x+3y)]/[(x^2-y^2)/(x^2+6xy+9y^2)]-xy/(x+y)=(x-y)/(x+3y)*(x+3y)^2/(x-y)(x+y)-xy/(x+y)=(x+3y)/
原式=(x-y)/(x+3y)×[(x+3y)^2/(x+y)(x-y)]-2y/(x+y)=(x+3y)/(x+y)-2y/(x+y)=(x+3y-2y)/(x+y)=(x+y)/(x+y)=1
第一项与第三项先合并9xy(x-y)(x+1)-3y(x-y)(3x+2y)+6y^2*(x-y)(x+1)=(x-y)(x+1)(9xy+6y^2)-3y(x-y)(3x+2y)=(x-y)(x+1
1、(-7x^y)(2x^y-3xy^3+xy)=-14x^(2y)+21x^(y+1)y^3-7x^(y+1)y;2、((x-y)^6)/((y-x)^3)/(x-y)=-(x-y)^3/(x-y)
XY/(X+Y)=3,XY=3(X+Y)原式=[6(X+Y)+4XY]/[9(X+Y)+4XY]=[6(X+Y)+12(X+Y)]/[9(X+Y)+12(X+Y)]=[18(X+Y)]/[21(X+Y
原式=-x²y+2xy²+2x²y²-4xy³-3x³+27x³y-18x²y²+2x²y-18x&
因为,x-y=3xy所以:-3x+6xy+3y/[(7x-5y)-9xy-(3x-y)]=[-3(x-y)+6xy]/[(7x-5y)-9xy-(3x-y)]=[-3*3xy+6xy]/[7x-5y-