5x xy-5y x-xy-y化简

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已知x2+y2-2x-4y+5=0,分式yx−xy

∵x2+y2-2x-4y+5=0,∴x2-2x+1+y2-4y+4=0,(x-1)2+(y-2)2=0,∴x=1,y=2,∴yx−xy=2-12=1.5;故答案为:1.5.

若x+y=4,xy=3,求yx

∵x+y=4,xy=3,∴原式=x2+y2xy=(x+y)2−2xyxy=16−63=103.

如果(x+1)^2+/y+2/=0,求代数式5xy-2/3x^3y^2-4yx+1/2y^2x^3-1/2xy-3x^3

没有写错啊(x+1)^2+/y+2/=0平方和绝对值的值恒为非负值只有两数都为0的时候,和才为0所以x+1=0,y+2=0x=-1,y=-2xy=25xy-2/3x^3y^2-4yx+1/2y^2x^

xy-3xy+2yx-yx

=xy-3xy+2xy-xy=-xy

-x^2y+5xy^2-yx^2合并同类项

-x^2y+5xy^2-yx^2=-2x^2y+5xy^2

已知1x−1y=3,则5x+xy−5yx−xy−y的值为(  )

根据分式的基本性质,分子分母都除以xy得,5y+1−5x1y−1−1x=−3×5+1−3−1=72.故选B.

化简:(1)3x2-[7x-(4x-3)-2x2](2)(2xy-y)-(-y+yx)(3)5(a2b-3ab2)-2(

(1)原式=3x2-7x+4x-3+2x2=(3+2)x2+(-7+4)x-3=5x2-3x-3;(2)原式=2xy-y+-y-yx=xy;(3)原式=5a2b-15ab2-2a2b+14ab2=(5

xy+yx=10x,y是多少

xy+yx=10x+y+10y+x=11x+11y=100+x10x=100-11yx=10-1.1y所以y只能是0

已知x-y=4xy,则2x+3xy-2yx-2xy-y

∵x-y=4xy,∴2x+3xy-2yx-2xy-y=2(x-y)+3xyx-y-2xy=8xy+3xy4xy-2xy=112.故答案为:112.

已知x+y=2,xy=-5,则yx+xy

yx+xy=x2+y2xy=(x+y)2-2xyxy当x+y=2,xy=-5时,原式=22-2×(-5)-5=-145.故答案为-145.

已知2的X次方等于5的Y次方等于10的Z次方,求证:XY=XZ+YX

XY=XZ+YX?那么也就是XY=X(Z+Y)咯,Y=Z+Y?无法证明的.题抄错啦~`

合并同类项:6x^2y+2xy-3x^2y^2-7x-5yx-4y^2x^2-6x^2y

6x^2y+2xy-3x^2y^2-7x-5yx-4y^2x^2-6x^2y=6x^2y-6x^2y+2xy-5yx-3x^2y^2-4y^2x^2-7x=-3xy-7x^2y^2-7x

已知xy满足x^2+y^2+4/5=2x+y 求代数式yx/x+y的值

你抄错题了吧X2+Y2+5/4=2X+Y移项,得(X-1)2+(Y-1/2)2=0X=1,Y=1/2

已知5x2-xy-6y2=0,则yx

∵5x2-xy-6y2=0,∴(5x-6y)(x+y)=0,∴5x-6y=0,x+y=0,∴5x=6y,x=-y,∴yx=56或-1.故答案为:56或-1.

有一排数字 比如:XY 把Y移到X前面得到YX 则YX为XY的两倍 请问这数是什么啊?这个数也可能是3位或4位或5位……

令2XY=YX2(10X+Y)=10Y+X解得X/Y=8/19貌似没有这样的两位数啊!至于3位,4位.你的题目没交代清楚啊!

求6x²y+2xy-3x²y²-7x-5yx-4y²x²-6x

6x²y+2xy-3x²y²-7x-5yx-4y²x²-6x²y|x+3|+(y+1/2)²=0x=-3y=1/2=-3xy-7x