4x^2-1 4y^2

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x/x-y*y^2/x+y-x^3y2/x^4-y^4/x^2/x^2+y^2

写清楚点点比如说前面是X/X还是X/(X-Y)打上括号分段这样才能清楚的做

6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5

设x-y=mx+y=n则6m-2n=143m+n=5解得m=2n=-1即x-y=2x+y=-1解得x=1/2y=-3/2

x+2y=-5&2x-5y=-1.3x=5y&2x-3y=-1 .2x+4y=11&3y-2y=3 .2x+3y=14&

x+2y=-5&2x-5y=-1由2式得:x=1/2×(5y-1);代入1式得:1/2×(5y-1)+2y=-5;y=-9/13;再代入1式得x+2×(-9/13)=-5得:x=-3×8/13

{(z+y)(x-y)-(x-y)的2次方+2y(x-y)}除以4y

(x-y)(z+y-x+y+2y)÷4y=(x-y)(z-x+4y)÷4y{(x+y)(x-y)-(x-y)的2次方+2y(x-y)}除以4y=(x-y)(x+y-x+y+2y)÷4y=(x-y)(4

(2x+y)(2x-3y)+x(2y+y) 2a(x-y)-4b(x-y)

(2x+y)(2x-3y)+x(2y+y)=(2y+y)(2x-3y+x)=(2y+y)(3x-3y)=3(2y+y)(x-y)2a(x-y)-4b(x-y)=2(x-y)(a-2b)

x^2-y^2/x+y-4x(x-y)+y^2/2x-y,

(x^2-y^2)/(x+y)-(4x(x-y)+y^2)/(2x-y)=(x-y)(x+y)/(x+y)-(4x^2-4xy+y^2)/(2x-y)=(x-y)-(2x-y)^2/(2x-y)=(x

(x+2)(x+3) (x-4)(x+1) (y+4)(y-2) (y-5)(y-3)

(x+2)(x+3)=x²+5x+6(x-4)(x+1)=x²-3x-4(y+4)(y-2)=y²+2y-8(y-5)(y-3)=y²-8y+15x²

计算【3(x-y)^2(x+y)^-2/4(x+y)^2(x-y)^-2】^-2

16(x+y)^8/9(x-y)^8=16/9*[(x+y)/(x-y)]^8哪个好理解用哪个.再问:有过程没。。。再答:这个过程其实没什么好研究的。。。[3(x-y)^2(x+y)^-2/4(x+y

(2x-y)^2-4(x-y)(x+2y)

4x^2+y^2-4xy-4(x^2-xy+2xy-2y^2)展开化简吧!

4x(y-x)-y^2因式分解

4x(y-x)-y²=4xy-4x²-y²=-(4x²-4xy+y²)=-(2x-y)²很高兴为您解答,【the1990】团队为您答题.请点

化简:{(x+2y)(2y-x)-4y(-x+y) } / (-2x)

{(x+2y)(2y-x)-4y(-x+y)}/(-2x)(4y²-x²+4xy-4y²)/(-2x)=x/2+4y

1) (2x+5y)(2x-5y)(-4x^2-25y^2) 2) [(x+y)(x-y)-(x-y)^2+2y(x-y

1)(2x+5y)(2x-5y)(-4x^2-25y^2)=-(4x^2-25y^2)(4x^2+25y^2)=-(16x^4-625y^4)=625y^4-16x^42)[(x+y)(x-y)-(x

(2x-y)(2x+y)-2(3x-4y)(4y+3x)

(2x-y)(2x+y)-2(3x-4y)(4y+3x)=4x²-y²-2(9x²-16y²)=4x²-y²-18x²+32y&s

化简:(2x-y)²-4(x-y)(x+y)

(2x-y)²-4(x-y)(x+y)=(4x²-4xy+y²)-4(x²-y²)=4x²-4xy+y²-4x²+4y&

1.((y+2x)(-2x+y)+4(x+2y)^2)/3y 2.(2(x-y)^3-8(x-y)^2(x+y)+6y(

1.((y+2x)(-2x+y)+4(x+2y)^2)/3y=(y^2-4x^2+4x^2+16xy+16y^2)/3y=(17y^2+16xy)/3y=17y/3+16x/32.(2(x-y)^3-

计算(x-2y)^2-4(2x+y)(y-2x)+4x(y-2)

(x-2y)^2-4(2x+y)(y-2x)+4x(y-2)=x^2-4xy+4y^2-4(y^2-4x^2)+4xy-8x=x^2-4xy+4y^2-4y^2+16x^2+4xy-8x=17x^2-

x+2y+4y^2/x-y+4x^y/4y^2-x^2

“4y^2/x-y”应该是“4y^2/x-2y”吧x+2y+4y^2/x-2y+4x^2y/4y^2-x^2=(x+2y)+4y^2/(x-2y)+4x^2y/(2y-x)(2y+x)=(x+2y)+

(x+3y-4)(2x-y)

原式等于2x^2-xy+6xy-3y^2-8x+4y=2x^2+5xy-3y^2-8x+4y

x+2y+4x^2y/4y^2+4y^2/x-2y

x+2y+4y^2/(x-2y)=((x+2y)(x-2y))/(x-2y)+4y^2/(x-2y)=(x^2-4y^2)/(x-2y)+4y^2/(x-2y)=x^2/(x-2y)或者是你的题说的有