4x^2 4x-15

两边乘22x+2x+48+x+4=14x14x-2x-2x-x=48+49x=52x=52/9

1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550120x=550x=55/12=4.583

[(X+3)/(X^2-4)-(-X)/(6-X-X^2)]/[1-(X^2-3X-15)/(X^2+X-6)]={(x+3)/[(x+2)(x-2)]-x/[(x+2)(x-3)]}/[(4x+9)

原式=[(1-1分之x+5)-(1-1分之x+4))+(1-1分之x+3)-(1-1分之x+2)]*[(x+3)(x+5)]\(x^2+7x+13)=[(1分之x+2)-(1分之x+3)+(1分之x+

15x=23x-248x=24x=312+5x=3x-82x=-20x=-103(x-3)=9-(x+6)4x=9+9-6=12x=34+x=4x-173x=21x=7

(x-1)(x-2)(x-3)(x-4)-24=[(x-1)(x-4)][(x-2)(x-3)]-24=[(x^2-5x)+4][(x^2-5x)+6]-24=(x^2-5x)^2+10(x^2-5x

6x=12x=22x=12x=6x=43+x=9x=63x-4-2x=1x=524-3x+12=x4x=36x=96x-4+x=177x=21x=3

x^4-4x^3-4x^2+15x+18=0x^4-3x^3-x^3+3x^2-7x^2+21x-6x+18=0(x-3)(x^3-x^2-7x-6)=0x1=3x2=3.49449283705542

设x1=4-√3,x2=4+√3,是方程X^2-8X+13=0的两根所以X1^2-8X1+15=2X^4-6X^3-2X^2+18X+23=(X+1)^2*(X^2-8X+13)+10=10所以原式=

2(4x-3)+(15-2x)=24+128x-6+15-2x=368x-2x=36-15+66x=27x=27÷6x=4.5

2（4x-3）+（15-2x）=24+128x-6+15-2x=366x+9=366x=27x=4.5

(x+1)(x+2)(x+3)(x+4)-24因式分解原式=[(x+1)(x+4)]*[(x+2)(x+3)]-24=(x^2+5x+4)*(x^2+5x+6)-24设A=x^2+5x,则原式=(A+

(4x+20)(x的平方-6x+9)/(3x-x的平方)(x的平方+2x-15)=4(x+5)(x-3)²/3（3-x）(x-3)(x+5)=-4/3

28X=84X=30.8X=60X=751.6X=8X=53X=24X=80.5X=1X=2再问：要过程啊我这是作业汗快点把我很急谢谢你啊再答：30X-2X=8428X=8428X÷28=84÷28X

亲,你这是问啥呢?再问：方程再答：（1）X=13(2)X=11(3)X=27/6你第三题我看不太明白是2（4X-3）+（15-2X）=24+12吗？如果是，那就是上述答案

(x^2+5x+4)(x^2+5x)+6(x^2+5x)+24=(x^2+5x)(x^2+5x)+4(x^2+5x)+6(x^2+5x)+24=(x^2+5x)(x^2+5x)+10(x^2+5x)+

中间两个括号结合,外边两个括号结合,这样就变成了：（x^2+5x+4)(x^2+5x+6)+24然后替代：设y=x^2+5x+4上式变为：y(y+2)+24这样方便运算,可以降幂.

*应该是÷原式=[(x+1)(x-1)-15]/(x-1)*(x-1)/(x-4)=(x²-16)/(x-1)*(x-1)/(x-4)=(x+4)(x-4)/(x-1)*(x-1)/(x-4

2x等于x+15x等于15