圆x^2 y^2-8x 6y 16=0与圆x^2 y^2=64的位置关系是
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y'=2-x的-2次方×8y'=2-8x^(-2)y′=2-8/x²
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=4x-2y-z-5x[6y-(x+y)]+x-(3y-10z)=4x-2y-z-30xy+5x²+5xy+x-3
(x+2y)(x-2y)-(2y-x)(-2x-y)=(x+2y)(x-2y)+(x-2y)(-2x-y)=(x-2y)[(x+2y)+(-2x-y)]=(x-2y)(-x+y)代入x=8y=-8=-
[(x+2y)(x-2y)-(x-2y)^2+8y(x+y)]/4x=[x^2-4y^2-x^2-4y^2+4xy+8xy+8y^2]/4x=12xy/4x=3y
两式相加2x-y+3x+y=7+85x=15x=3y=2x-7=2x3-7=-1如果本题有什么不明白可以追问,
1:x+y=222:2x-y=81+2x+y+(2x-y)=22+8x+2x+y-y=303x=30x=1010+y=22y=12希望能够帮助你!
解13x-2y=9x-3y=2将式2左右两边同时乘以3得3x-9y=6与式1相减有-9y+2y=6-9解得y=3/7代入代2有x-3*3/7=2解得x=23/7故x=23/7y=3/7解2x+y=5x
根号(x+y-8)+根号(8-x-y)=根号(3x-y-4)+根号(x-2y+7),根据二次根式有意义得:X+Y-8≥0,8-X-Y≥0,∴X+Y≥8,X+Y≤8,∴X+Y=8,左边为0,右边两个非负
(x+y)/x=11/88x+8y=11y8x=3yy=8x/3(x-y)/(x+2y)=(x-8x/3)/(x+16x/3)=(-5x/3)/(19x/3)=-5/19
3x=8yx/y=8/3(1)x+y/y=x/y+1=8/3+1=11/3(2)2x+3y/x-2y分子分母同时除以y得=(2x/y+3)/(x/y-2)=(16/3+3)/(8/3-2)=(25/3
√(x²+y²-2x-2y+2)化为√(x-1)²+(y-1)²就是求圆x²+y²+8y+12=0到(1,1)距离最小和最大.x²
X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1
因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6
先一个一个的展开括号项,再同项合并就行了啊[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x=[xx-xy-(xy-yy)+x(x-y)+y(x-y)]÷2x=[xx-xy-xy+yy+xx-
这是一道简单的数学题.你应该加强学习了首先可以整理出圆的规范方程C1:(X-1)^2+(Y-2)^2=9可以知道圆心是(1,2)半径是3C2:(X-4)^2+(Y+2)^2=16可以知道圆心是(4,-
x平方+8x+16+y平方+6x+9=0(x+4)平方+(y+3)平方=0∴x+4=0y+3=0∴x=-4,y=-3原式=(x+2y)(x-2y)/(x+2y)平方-x/(x+2y)=(x-2y)/(
你确定答案是-14
解9y=3x-(x-1)2x-9y+1=0①4(x+y)-(2x+4)=8y2x-4y-4=0②②-①得:5y-5=0∴y=1将y=1代入①得:2x-9+1=0∴x=4∴方程的解为:x=4,y=1
x+y/y=11/8说明11y=8(x+y)即8x=3y所以x-y/x+2y=3(x-y)/3(x+2y)=(3x-3y)/(3x+6y)=(3x-8x)/(3x+16x)=-5/19