3分之x-y=4分之2y-z=5分之2z x=1,求x,y,z的值
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设x=2K.Y=3k.Z=4kx-y+z分之x+y-z=(2k-3k+4k)分之(2k+3k-4k)=3k分之k=3分之1
x=2y/3x=4y/32y/3+2y+4y/3=64y=6y=3/2x=1z=2
你好!设(x+2y)/3=(y+3z)/4=(z+5x)/5=k则x+2y=3ky+3z=4kz+5x=5k解方程组得x=25k/31y=34k/31z=30k/31故x:y:z=25:34:30已经
(X+4)/3=(Y+3)/2=(Z+8)/4,得x=(3y+1)/2,z=2y-2,(3y+1)/2+y+2y-2=12,y=3,x=5,z=4
令2分之x=3分之y=4分之z=k,则x=2k,y=3k,z=4k,(x+3y-2z)/(2x+y)=(2k+9k-8k)/(4k+3k)=(3k)/(7k)=3/7
因为2x=3y=4z可得,x=2z,y=4/3z代入2x-y+z=11/3zx+y+z=13/3z2x-y+z分之x+y+z的值等于13/11
解由5分之x=4分之y=3分之z令5分之x=4分之y=3分之z=k则x=5k,y=4k,z=3kk不等于0则3x-2y分之x+y+z=(3x-2y)分之(x+y+z)=(3*5k-2*4k)分之(5k
又(X+4)/3=(Y+3)/2=(Z+8)/4得出X=3/2Y+1/2Z=2Y-2再带入X+Y+Z=12得出3/2Y+1/2+2Y-2+Y=12得出Y=3再得出X=5,Z=4
令2分之x=3分之y=4分之z=k,则:x=2ky=3kz=4kx+y+z=1/12,得:2k+3k+4k=1/129k=1/12k=1/108所以:x=2/108=1/54y=3/108=1/36z
令a=x/3=y/4=z/5所以x=3ay=4az=5a所以3a-8a+15a=3010a=30a=3所以x=9,y=12,z=15
1.令x/2=y/3=z/4=k,则有:x=2ky=3kz=4k所以:(2x+y-z)/(x+y+z)=(2×2k+3k-4k)/(2k+3k+4k)=1/32因为x^2+y^2+2x+4y+4=0即
因为x/3=y/4=z/5所以可令x=3k,y=4k,z=5k.(k不为0)所以带入得:(3x-2y+z)/(x+y+z)=1/2再问:为什么等于1/2--嗯题是x+y+z/3x-2y+z.....不
解x/2=y/3=z/4=k∴x=2k,y=3k,z=4k∴(2x+y-z)/(3x-2y+z)=(4k+3k-4k)/(6k-6k+4k)=3k/4k=3/4
令x/3=y/4=z/5=t则x=3t,y=4t,z=5t(x+2y+3z)/(2x+y-z)=(26t)/(5t)=26/5
因为2分之x=3分之y=4分之z,设2分之x=3分之y=4分之z=A,得X=2A,Y=3A,Z=4A(X+2Y-3Z)/(2X-Y+3Z)=-4/13
这数据没问题?或者是我算错了,你参考一下,方法如此.由题:16x/3=z/5-2y1式9y/4=x/3-3z2式16z/5=y/4-5x3式由1和2:16x/3=z/5-8(x/3-3z)/9x:z=
由题可得:x/2=y/3=z/4,化简得:6x=4y=3z,由此可得x=1/2z,y=3/4z,所以,(x+y-z)/(x+y+z)=(1/4z)/(9/4z)=1/9
解:不防设x=2A,则y=3A,z=5A.由x+y+z=20,可知2A+3A+5A=20,10A=20,A=2.则x=4,y=6,z=10.
设2分之x+y=3分之y+z=5分之x+z=k则x+y=2k,y+z=3k,x+z=5k3式相加得2(x+y+z)=10k=18*2=36,k=3.6,x+y+z=5kz=5k-2k=3k=10.8x