3x^2 1-3x 7-3x^2 5
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#include"stdafx.h"#include"iostream"#include<stdio.h>#include<stdlib.h&
这是sin(x)的Taylor展开,对哪个编程?再问:wintc吧简单点尽量用数组谢谢
2(x³)²·x³—(3x³)³+(5x)^2·x^7=2x^9-27x^9+25x^9=0
特点是10位以上相同,个位数相加为10734*736=73*(73+1)*100+4*6=540224
1/(1x4)+1/(4x7)+1/(7x10)+...+1/(3n-2)x(3n+1)]=1/3*(1-1/4+1/4-1/7+.+1/(3n-2)-1/(3n+1))=1/3*(1-1/(3n+1
100x(3/1x4+3/4x7+3/7x10+.3/97x100)=100x[(1-1/4)+(1/4-1/7)+(1/7-1/10)+……+(1/97-1/100)]=100x[(1+1/4+1/
f(3)=((((((7*3+6)*3+5)*3+4)*3+3)*3+2)*3+1)*3
-10.5x(-6分之1-4分之1)x7分之3除以(-0.5)=10.5x(6分之1+4分之1)x7分之3×(-2)=10.5x12分之5x7分之3×(-2)=10.5x7分之3x12分之5×(-2)
2.7x+3=97.52.7x=97.5-3x=94.5÷2.7x=350.95÷0.4x=1.90.4x=0.95÷1.9x=0.5÷0.4x=1.256.8+x=24.5x=24.5-6.8x=1
1/1X3+1/3X5+1/5X7+.+1/(2x-1)(2x+1)=10/211/2*(1-1/3)+1/2*(1/3-1/5)+1/2*(1/5-1/7)+.+1/2*[1/(2x-1)-1/(2
原式=1/3(1-1/4+1/4-1/7+……+1/3n-2-1/3n+1)=1/3(1-1/3n+1)=1/3(3n/3n+1)=n/3n+1
(x7+px+q)(x2+2x-3)=x^9+2x^8-3x^7+px^3+2px^2-3px+qx^2+2qx-3q;不含x^2和x^3;所以p=0;2p+q=0;q=0;如果本题有什么不明白可以追
10x^9+9x^8+8x7+7x^6+6x^5+5x^4+4x^3+3x^2+2x^1+1,当x=-1时的值为10x^9+9x^8+8x7+7x^6+6x^5+5x^4+4x^3+3x^2+2x^1
7^4-3x7^2-8x7^3=7^2x(7^2-3-8x7)=7^2x(49-3-56)=49x(-10)=-490(x+y)^2-2(x^2-y^2)+(x-y)^2=(x+y)^2-2(x+y)
0.9x-4X1.3=1.10.9x-5.2=1.10.9x=1.1+5.20.9x=6.3x=71.3X7=25.1-8x9.1=25.1-8x8x=25.1-9.18x=16x=24.8+0.5x
0.9x--4x1.3=1.10.9x-5.2=1.10.9x=6.3x=71.3x7=25.1-8x9.1=25.1-8x8x=16x=24.8+0.5x=6.30.5x=1.5x=3(25+2x)
原式=-13×(2/3+1/3)-0.34×(5/7+2/7)=-13-0.34=-13.34
第一题约分7.5和2.5,4.8和1.6分子约分剩余9再和分母剩余的3约掉,最后9.1x3第二题把括号拆开68.3+11.7-24.2第三题3.6和0.9约剩4,再和80约,最后是125X20是这个意
48-X+3x7=3648-x+21=36-x=36-48-21-x=-33x=33
(-217又7/9)-(-7)=-217-7/9+7=-217+7-7/9=-210-7/9=-210又9分之7-22/7x(7/22-4/3)x7/22÷(-22/21)=-22/7*7/22*(7