3 10x²-2 15y²分之3 2x²-2 3y²

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(X+Y分之X+X+Y分之2Y)乘X+2Y分之XY除以(X分之1+Y分之1)要有过程

原式=[(x+2y)/(x+y)][xy/(x+2y)]÷[(x+y)/xy]=[xy/(x+y)]×xy/(x+y)=x²y²/(x+y)²

画出y=x分之1(x

这是反比例函数.图像是位于一、三象限的双曲线.由于x<0,因此函数图象为双曲线的第三象限部分手工绘图应用描点法.见下图

【x-y-(x-y分之4y平方)】【x+y-(x+y分之4x平方)】除以【3(x+y)-x-y分之8xy】

【x-y-(x-y分之4y平方)】【x+y-(x+y分之4x平方)】除以【3(x+y)-x-y分之8xy】=(x-y-x+4y)(x+y-x-4x/y)/(3x+3y-x-8x)=3y*(y-4x/y

若z分之x+y+z=y分之x-y+z=x分之-x+y+z,求xyz分之(x+y)(y+z)(z+x)

设(x+y-z)/z=(x-y+z)/y=(-x+y+z)/x=k则(1)x+y-z=kz(2)x-y+z=ky(3)-x+y+z=kx(1)+(2)+(3)得x+y+z=k(x+y+z)∴k=1时,

1 x^2y分之x^4

1x^2y分之x^4=x²/y2ab分之ab-b^2(b不等于0)=1-b/a36abc^2分之36ab^3c=6b²/c4a^2-b^2分之(a+b)^3=(a+b)²

x分之y+z=y分之z+x=z分之x+y(x+y+z不等于0),求x+y+z分之x+y-z

令(y+z)/x=(z+x)/y=(x+y)/z=ky+z=kxx+z=kyx+y=kz2(x+y+z)=k(x+y+z)2(x+y+z)=k(x+y+z)(2-k)(x+y+z)=0(x+y+z≠0

若x分之5=y分之3,则x+y分之x-y=

x=三分之五y代入x+y分之x-y消去y得:四分之一

双曲线9分之X²-16分之Y²=1的两个焦点为F1,F2,点

解题思路:双曲线的定义解题过程:varSWOC={};SWOC.tip=false;try{SWOCX2.OpenFile("http://dayi.prcedu.com/include/readq.

计算:1、(xy分之x²-y²)×(x-y分之x)-(y分之x);

1、(xy分之x²-y²)×(x-y分之x)-(y分之x);=(x+y)(x-y)/xy×x/(x-y)-x/y=(x+y)/y-x/y=(x+y-x)/y=12、6xy²

(x+y分之x加x+y分之2y)乘x+2y分之xy除(x分之1加y分之1)等于?

原式=[(x+2y)/(x+y)]×[xy/(x+2y)]÷[(x+y)/xy]=[(x+2y)/(x+y)]×[xy/(x+2y)]×[xy/(x+y)]=x²y²(x+2y)/

x减y分之x加y乘以x加y分之x减y

是(x-y)分之(x+y)*(x+y)分之(x-y)如果是,那么:(x-y)分之(x+y)*(x+y)分之(x-y)=1

通分:x+y分之x-y,x²+xy分之x,x²-y²分之y

(x-y)/(x+y),x/(x²+xy)=1/(x+y),y/(x²-y²)=y/(x+y)(x-y)分母的最小公倍数是(x+y)(x-y)通分得:(x-y)/(x+y

通分x+y分之x-y,x-y分之x+y

x+y分之x-y=(x-y)²/(x+y)(x-y)x-y分之x+y=(x+y)²/(x+y)(x-y)

(x-4y)分之(3x)+(4y-x)分之(x+y)-(x-4y)分之(7y)

=3x/(x-4y)-(x+y)/(x-4y)-7y/(x-4y)=(3x-x-y-7y)/(x-4y)=(2x-8y)/(x-4y)=2(x-4y)/(x-4y)=2

解方程x²分之x²-xy÷(y分之x-x分之y)

中间是÷?再问:不是,写错了,是分解应试再问:(x²分之x²-xy)÷(y分之x-x分之y)再答:这是计算吧,怎么可能是因式分解再问:那你按计算做再答:原式=【x²分之x

x+3y=3,求x²-9y分之2x-6y的值

解题思路:本题目应该是9y的平方吧,要不然没法做出来。解题过程:(2x-6y)/(x的平方-9y)=2(x-3y)/[(x-3y)(x+3y)]=2/(x+3y)=2/3

解方程组:5分之x+1减2分之y-1=-1 ,3x+4y=32

将(1)式通分后得到2x+2-5y+5=-10整理得到2x-5y=-17再将其乘以3,得到6x-15y=-51(3)式将(2)式乘以2,得到6x+8y=64(4)式用(4)—(3),得到23y=115

x-4y分之3x + 4y-x分之x+y - x*x-4y分之7y

x-4y分之3x+4y-x分之x+y-x-4y分之7y=3x/(x-4y)-(x+y)/(x-4y)-7y/(x-4y)=(3x-x-y-7y)/(x-4y)=(2x-8y)/(x-4y)=2

(x+y分之x + x+y分之2y)乘x+2y分之xy 除以(x分之1+y分之1)同样用两...

是这样的形式吗?[x/(x+y)+2y/(x+y)]×[xy/(x+y)]÷(1/x+1/y)一:原式=(x+2y)/(x+y)×[xy/(x+2y)]÷[(x+y)/xy]=x²y&sup