作业帮2倍log3底2等于几
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log(8)9·log(3)4=(lg9/lg8)·(lg4/lg3)=(2lg3/3lg2)·(2lg2/lg3)=4/3
题目错了再问：没。。。我算出来了。。等于lg2再问：...是错了。。乘以再答：求好评，亲
log3[log3（log5a）]=0log3（log5a）=1log5a=3a=625log4[log4（log5b）]=0log4（log5b）=1log5b=4b=125所以a/b=625/12
2√3÷√2=2√（3×2）÷√（2×2）=（2√6）÷2=√6
log2(3)+log3(5)+log3(2)=log2(3)+log3(10)=4.2429387700296再问：=1g3/1g2+(lg5+lg2)lg3这个式子最后那个lg3原来是分母，，怎么
log7[log3(log2x)]=0所以log3(log2x)=1所以log2x=3所以x=8求的式子没看懂,自己算算
等于2/a利用换底公式,log3^2=log2^2/log2^3=a,即log2^3=1/a;log2^9=log2^(3^2)=2log2^3=2*(1/a)=2/a
=(lg2/lg3)*(lg9/lg8)(换底）=(lg2*lg9)/(lg3*lg8)=(lg2*2lg3)/(lg3*3lg2)=2/3
log4(9)=2*1/2log2(3)=log2(3)log3(4)=2log3(2)log9(2)=1/2log3(2)[log2(3)+log4(9)][log3(4)+log9(2)]=2lo
log3(x²-10)=1+log3(x)log3(x²-10)=log3(3)+log3(x)log3(x²-10)=log3(3x)x²-10=3xx1=-
用换底公式：2的常用对数除以3的常用对数再乘3得：3×0.301/0,4771=1.89268497
利用公式lga^b=blga知：lg25=2lg5,lg9=2lg3,lg2倍根号2=(3/2)*lg2log2^25*log3^2倍根号2*log5^9（利用loga^b=lga/lgb,化成同底形
(1).2log₃2-log₃(32/9)+log₃8=2log₃2-(5log₃2-2)+3log₃2=2(2).(9/4)^
log2^5*log3^2倍根号2*log5^9=lg5*lg2倍根号2*lg9/(lg2*lg3*lg5)=3*lg5*lg2*lg3/(lg2*lg3*lg5)=3再问：log2^25*log3^
log3(log2x)=1log2x=3^1=3x=2^3=8x^(1/2)=√8=2√2
如果你的问题是：log3(x^2+2)=（log3x）+1则是下面答案：先建立方程：x^2+2=3x（X>0）解答上面方程x^2-3x+2=0得到结果：x=1或x=2
（2+log3x)log3x>log3(9x)=>（2+log3x)log3x>log3(9)+log3(x)=>（2+log3x)log3x>2+log3(x)设log3(x)=t=>(2+t)t>
2倍（a+1)乘以(a+1)=2(a+1)^2
log32等于log23的x次方x=-1因为log32与log23互为倒数.
答案是3/25