2x y分之4x²-4xy y²÷(4x²-y²)-搜答案-拍题作业网

原式=（2x+y）/（5xy-6xy）×（1/2）（x+2y）=（x+y）/（-xy）×（1/2）（x+y）=（-xy）/（2x+2y）=（-xy）/2(x+y)=（1/2）×（-xy）/(x+y)当

原式=[x-y(x-y)2-y(x+y)(x+y)(x-y)]•xyy-1=（1x-y-yx-y）•xyy-1=1-yx-y•xyy-1=-xyx-y．故答案是：-xyx-y．

原式=(x+2y)(x-2y)/(x+y)^2*2x(x+y)/x+2y=2x(x-2y)/(x+y)很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,

=-(x+2y)(x-2y)/(x+y)²×2x(x+y)/(x-2y)=-2x(x+2y)/(x+y)=-(2x²+4xy)/(x+y)

=(2X/3Y)*(3X/4Y)*(4/xy)=(2x*3x*4)/(3y*4y*xy)=2x/(y^3)

因为x-y=4xy所以x-2xy-y=2xy2x+3xy-2y=11xyx-2xy-y分之2x+3xy-2y=5.5

x平方+y平方+2xy分之x平方-4y平方除以x平方+xy分之2y+x=(x-2y)(x+2y)/(x+y)²·x(x+y)/(x+2y)=x(x-2y)/(x+y)

题目是√x^3+X^2y+1/4xy+√(1/4x^3)-X^2y+xy^2如果是：√x^3+X^2y+1/4xy+√(1/4x^3)-X^2y+xy^2=(3/2)√x^3+xy/4+xy^2=(3

原式=[(x+y)2(x-y)(x+y)+-4xy(x-y)(x+y)]×(x+3y)(x-3y)(x+3y)(x-y)=x-3yx+y，由已知得（3x-2y）（x+y）=0，因为x+y≠0，所以3x

x²+y²+2xy分之x²-4y²÷x²+xy分之2y+x=(x+2y)(x-2y)/(x+y)²×x(x+y)/(x+2y)=x(x-2y

产生4种配子xyxyyyx有一种y有两种xy1y2xy1xy2y1y2产生的配子如上y1、y2是一个意思所以分为一组xyxyyy=1221

[4(xy-1)^2-(xy+2)(2-xy)]除以4分之1xy=[4x^2乘以y^2-8xy+4-(4-x^2y^2)]除以4分之1xy=(4x^2乘以y^2-8xy+4-4+x^2y^2)除以4分

由已知条件可得：x-y=-4xy,（也就是在等式两边乘xy后整理,即可）,代入所求的式子里分母为-4xy+7xy,即3xy；分子为-4xy-2xy,即-6xy,化简得-2

=xy(1-2y^2)=-0.119616

（1）（2）(x-1分之x+2)+(x-1分之-3)=2乘以x-1得x+2-2=2x-2x-2x=-2x=2（3）(x+2分之1)+(x分之1)=x²+2x分之32乘以x(x+2)得x+x+

[(xy-2)(-xy-2)-4(xy-1)^2]除以(-xy)=[-x²y²+4-4(x²y²-2xy+1)]÷(-xy)=(-x²y²+

[(xy+2)(xy-2)-2x的平方y的平方+4]÷（-xy)当x=10,y=25分之1=[x^2y^2-4-2x^2y^2+4]÷（-xy)=[-x^2y^2]÷（-xy)=xy=10*1/25=

（xy-x的平方）÷xy分之x-y=x(y-x)*xy/(x-y)=-x^2y(x的平方+x分之4x的平方-1）乘(1-2x分之x+1)÷x分之1=[x(x+1)分之(2x+1)(2x-1)]乘(1-