2m-n-4=3m 4n-1=1-搜答案-拍题作业网

(M-N/根号M-根号N)+(M+4N-4根号MN/根号M-2N)=(根号M+根号N)+(根号M-2根号N)=2根号M-根号N=2根号3/3-根号3/9=根号3/3

4m²-5m【-m＋2n-1】＋4m【-2m-3n＋2】=4m²＋5m²-10mn＋5m-8m²-12mn＋8m=m²-22mn＋13m因为m=2,n

m4n-2等于1,3m-2n+2等于1,然后解出来

n/m=3/4m/(m+n)=1/[1+n/m]=4/7n/(m-n)=1/[m/n-1]=3m^2/(m^2-n^2)=1/[1-n^2/m^2]=16/7所以原式=9/7当然,你可以通分来算,也能

易知函数f(x)=3^x+6x-1在x＞0时是增函数,因此m随着n的增大而增大,然后就列举计算来求啦,没别的好办法,n=1,m=3+6-1=8＜2000；n=2,m=9+12-1=20＜2000；n=

原式=[(√m)²-(√n)²]/(√m-√n)+(√m-2√n)²/(√m-2√n)=√m+√n+√m-2√n=2√m-√n当m=1/3n=1/27时,原式=2√（1/

[(3m+2n)(3m-2n)-(m+2n)(5m-2n)]÷(1/3)m=[9m²-4n²-5m²+2mn-10mn+4n²]÷(1/3)m=[4m²

(m-n)*(3m-2n+1)=?

原式=m(3m-2n+1)-n(3m-2n+1)=3m²-2mn+m-3mn+2n²-n=3m²-5mn+2n²+m-n

6m^2-5m(-m+2n-1)+4m(-3m-5/2n-3/4)=6m²＋5m²－10mn＋5m－12m²－10mn－3m=﹣m²－20mn＋2m=﹣m(m＋

答：(5m+3n)^2-(m-3n)(25m-3n),其中m=1,n=2=25m²+30mn+9n²-(25m²-3mn-75mn+9n²)=30mn+78mn

你好!数学之美团为你解答1+(n-m)/(m+2n)÷(m²-n²)/(m²+4mn+4n²)=1+(n-m)/(m+2n)×(m+2n)²/[(m+

C(m+1,n)=C(m,n-1)+C(m+1,n-1)这个式子可以直接验证,也可以算两次得证.然后递推C(m+1,n)=C(m,n-1)+C(m+1,n-1)=C(m,n-1)+C(m,n-2)+C

4.5*5=4.5+(4.5+1)+(4.5+2)+(4.5+3)+(4.5+4)+4.5+5)=4.5x6+1+2+3+4+5=27+15=42m*8=37.8m*n=m+(m+1)+(m+2)+(

=(m^2-n^2)(-m^2-n^2)-(4m^2-n^2)(4m^2+n^2)=-(m^4-n^4)-(16m^4-n^4)=-（1^4-（-2)^4）-(16*1^4-(-2)^4)=15

原式=4m²-n²+mn+2n²-4m²-4mn-n²=-3mn

[(3m-n)^2-(3m-n)(3m+n)-4mn]/(2n)=[（9m²+n²-6mn）-（9m²-n²）]/(2n)=(9m²+n²-

1/2（m-n)+1/4(m+n)+m+n/3-m-n/6=1/2m-1/2n+1/4m+1/4n+m+n/3-m-n/6=(1/2m+1/4m+m-m)+[(-1/2n+1/4n)+（n/3-n/6

既然m-3n+4=0那么m-3n肯定等于-4,再把-4带进去算就是了

将（2m-n）看成整体,值为3方程（2）-（1）x2得,5n=-5由方程（1）两边同时乘以-1得,n-2m=-3将以上所得的值带入5n(2m-n)^-2(n-2m)^中即得要求的值!