/x-1/ y²-4y 根号z 4
来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 16:58:10
√xy-√x/y=√5·4-√5/4=2√5-√5/2=3√5/2
解∵x+2y≥0∴√(x+2y)×√(2x+4y)=√2√(x+2y)²=√2(x+2y)
因为根号[4x-y+11]+根号[1/3y-4x-3]=0,所以4x-y+11=0,1/3y-4x-3=0解方程组得x=5/2,y=21代入2x根号[x/y]*1/2y根号[y^2/x]即可解得
解由题意得;4+x=0y-2=0解得x=-4y=2∵愿式=2×〔-4)-2=-10解根号〔3×2.5×30)=15
根号x-4+绝对值y+1=0,求根号X的y方√(X-4)+/y+1/=0因为√(X-4)与/y+1/均为大于等于0的实数,要他们相加等于零,那么只有他们分别为O的时候才可以(关键思路)所以x-4=0,
很高兴喂你解答!原式=4√[(x^2+xy+y^2)/(x-y)*1/2√[(x^2-xy+y^2)/(x+y)*3√(x^3+y^3)=6√[(x^2+xy+y^2)/(x-y)*√[(x^2-xy
根号内必须大于等于0故有x-1≥0且1-x≥0即x≥1且x≤1所以x=1将x=1代回去得y=3然后将x,y代入所求式即可你的所求式表述不是很清楚,所以没办法帮你求了
因为4x^2+9y^2-4x-6y+2=0,所以4x^2-4x+19y^2-6y+1=0,(2x-1)^2+(3y-1)^2=0所以2x-1=0,3y-1=0,所以x=1/2.y=1/3所以根号y/(
根号(x+y-8)+根号(8-x-y)=根号(3x-y-4)+根号(x-2y+7),根据二次根式有意义得:X+Y-8≥0,8-X-Y≥0,∴X+Y≥8,X+Y≤8,∴X+Y=8,左边为0,右边两个非负
1-4x≥0;x≤1/4;4x-1≥0;x≥1/4;∴x=1/4;y=1/2;原式=√(1/2+2+2)-√(1/2-2+2)=3√2/2-√2/2=√2;很高兴为您解答,skyhunter002为您
(x+y+z)^2=[(x+y)+z]^2=(x^2+2xy+y^2)+z^2+2zx+2zy=x^2+y^2+z^2+2xy+2xz+2yz=x^2+y^2+z^2+2(xy+xz+yz)=0x+y
额,题目很长,我读出二层意思,题中有2个/,哪一个最长啊?也就是哪个是哪个的被除数.
设x2=y3=z4=k,则x=2k,y=3k,z=4k,∵2x-3y+4z=22,∴4k-9k+16k=22,∴k=2,∴x+y-z=2k+3k-4k=k=2.
是根号x+y-1+(y+4)²=0所以x+y-1=0y+4=0所以y=-4x=1-y=5所以x-y=5+4=9
设x+3y3=2y+3z4=2z+2x5=k,则有:x+3y=3k2y+3z=4k2z+2x=5k,解得x=32ky=12kz=k;因此x:y:z=3:1:2.
y=x/2-√(x-2)+2√(2-x)被开方数大于等于0x-2≥0且2-x≥0x≥2且x≤2所以x=2y=1√(4x+y)-√(x²+5y)=√(4*2+1)-√(2²+5)=0
(注:表示根号)a有意义=>a>=0;y=(x-4)+(4-x)+1=>x-4>=0且4-x>=0=>x=4=>y=1=>x:y=4:1
解√4y^5-4xy^4+(x²y³)=√y³(4y²-4xy+x²)=√y³(2y-x)²∵y>1/2x且y≥0∴2y-x>0∴
先对式子化简对分母x^2-y^2/x^2+4xy+4y^2=(x+2y)^2-y^2/x^2=(x+2y-y/x)(x+2y+y/x)原式=(x-y/x+2y)/(x+2y-y/x)(x+2y+y/x