创建一个函数,判断用户输入的数字是否为质数?

不用创建函数CASEWHENdigit>0THEN'+'WHENdigit=0THEN'0'ELSE'-'ENDSELECTnumberfromnum1WHEREnum1>0

是VB吗再问：恩再答：X=inputbox（“输入”）iffix（x）=xthenifx/2=0thenprintx+“为偶数”elseprintx+“为奇数”endifendif再答：X=input

#!/bin/bashread -p 'please input A1:' aread -p 'pleas

21,22?2的1-10次幂不是2,4,8,16.#include#includeusingnamespacestd;intmain(){\x05inti,n,s=0;\x05intm[10];\x0

用C++语言编写：#include <iostream.h>class Matrix{private:\x05int row,colomn;public:\x

else没有跟if对上你这个求素数的算法也错了

#includeintfunc(intm){inti;for(i=2;i*i>m;\x05if(func(m))\x05{\x05\x05cout

#includemain(){intn;printf("Pleaseenteranumber:");scanf("%d",&n);if(n%2==0)printf("Thenumber%dis偶数\n

if(flag==0){\x05intiLast,iNext;\x05iLast=sqrt(nums);\x05iNext=iLast+1;\x05printf("itisnotaperfectsqu

#includeintisprime(intn){\x09if(n

我用C语言编一下啊.其他语言类似!#includevoidsort(intn){if(n%2==0)printf("thenumberisdouble\n");elseprintf("thenumbe

FunctionGetOE(NumAsLong)AsStringGetOE=IIf(NumMod2,"奇数","偶数")EndFunctionPrivateSubCommand1_Click()Msg

#includevoidmain(){doublea,b;printf("请输入两个数a,和b\n");scanf("%lf%lf",&a,&b);printf("两个数和是:%lf\n",a+b);

这个应该符合你的要求#include#includeboolshuixian(intnumber){intz,y,x;z=number/100;y=(number-100*z)/10;x=number

打开资源管理器,点底下新任务--输入进程名称

因为你最后Console.ReadKey();是读取键盘输入的值,所以回车键也算做输入内容,格式提示转换错误.while(true){Console.WriteLine("请输入数字");string

importjava.util.*;publicclassMath{publicstaticvoidmain(Stringargs[]){inta,b;Scannersc=newScanner(Sys

#includeusingnamespacestd;voidzhuanzhi(int*,intr,intc);intmain(){introw,col;int*mat=0;coutrow>>col;m

当使用远程处理时,对于任何用户定义的异常的元数据,都必须确保其在服务器（被调用方）和客户端（代理对象或调用方）上均可用.

#include#includeinti=0;voidisPro(intn){if(n==0)return;else{i*=10;i+=n%10;isPro(n/10);}}v