.参数方程x=1 t,y=1 t(t^2-1)(t为参数)所表示的曲线是-搜答案-拍题作业网

t+1/t=x/sinθt-1/t=y/cosθ两式相加：2t=x/sinθ+y/cosθ两式相减：2/t=x/sinθ-y/cosθ此两式相乘：4=x^2/(sinθ)^2-y^2/(cosθ)^2

x=t+1/t,y=t-1/tx^2-y^2=4

x=y^2-y-2再问：求解答过程再答：y=t-1,t=y+1,代入，x=(y+1)^2-3(y+1)+1=y^2+2y+1-3y-3+1=y^2-y-1检验的时候发现上面回答的错了，答案是y^2-y

x-1=(t+1)/(t-1)-1=2/(t-1)t-1=2/(x-1)t=(x+1)/(x-1)t^2+t+1=(x+1)^2/(x-1)^2+(x+1)/(x-1)+1=(3x^2+1)/(x-1

3X+5Y-11=0由X=－3+（5/T+1）Y=4－（3/T+1）两式得

由x=t+1/t,可得x>=2或x=2或x

应该是两条射线.因为x=t+1/t,由均值不等式可知,x>=2或x=2或x

x+y=2/tx-y=2tx+y=4/(x-y)x^2-y^2=4

t^2=(x-2)/3=y+1x-3y-5=0t^2>=0所以(x-2)/3>=0,x>=2y+1>=0,y>=-1所以不是整条直线而是(2,1)右边的部分所以是一条射线

X=t+1/tY=t-1/t都平方得X^2=t^2+2+1/t^2,Y^2=t^2-2+1/t^2X^2-Y^2=4

x-2y=t-1t=x-2y+1代入y=t^2-t-1得y=（x-2y)(x-2y+1)-1整理得x^2-4xy+4y^2+x--3y-1=0

-4t=2x-6=y+12x-y-7=0

x+y=2tx-y=2/t(x+y)*(x-y)=4

x=t+1/ty=t-1/t两式相加得：t=(x+y)/2代入其中1式得：x=(x+y)/2+2/(x+y)化为：x^2-y^2=4此为双曲线.

dy/dx=(dy/dt)/(dx/dt)dy/dt=-4t^3dx/dt=e^t+(t-1)e^t=te^t所以dy/dx=-4t^2/e^t

先问一下楼主：x=-t²+1/t²+1还是x=-t²+1/(t²+1)?y=t/t²+1还是y=t/(t²+1)?OKx²=t&s

y=(1-x)*4/3

x²+y²=4(1+t²)/(1+t²)²=4/(1+t²)=2x整理得到：(x-1)²+y²=1如果用圆的参数方程表示

x=t+1/t的最大值为-1,故方程化为普通方程为y=0(x

X=T+1/T(T+1/T)X=(T+1/T)^2T^2+1/T^2=(T+1/T)X-2Y=(T+1/T)X-2