-6x平方y-3x立方-3xy平方
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4x^2y-(3x^3+2xy^2-x^2y)+(y^2x+3x^3+3)=5x^2y-xy^2+3=-60-18+3=-75再问:==、就是先化简(去括号,合并同类项)再求值
(8x²y-2xy²-3y³)分之(6x³-5x²y-4xy²)=[y(8x²-2xy-3y²)分之x(6x²
原式=x³+3x²y-5xy²+6y³+1-2x³+y³+2xy²+x²y+2-4x²y-7y³+x
y=(2/3)xy²=(4/9)x²y³=(8/27)x³所以原式=[3x³+(8/3)x³-(20/9)x³-(8/27)x&s
(x的立方-4x的平方y+11xy的平方-y的立方)+(7x的平方y-16xy的平方+y的立方)=x的立方+3x的平方y-5xy的平方很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么
(3x^2+4xy^2-y^3)(-x^2y)^3=-3x^8y^3-4x^7y^5-x^6y^6是直接拆开的吧
原式=-y(9x²-6xy+y²)=-y(3x-y)²
=-3x(x^2+2xy+2y^2)
3x³-12x²y+12xy²=3x﹙x²-4xy+4y²﹚=3x﹙x-2y﹚²
解(-3x²y)(-4x²y²-5y³-6x+1)=(-3x²y)(-4x²y²)+(-3x²y)(-5y³)
【】=(X³-3X²Y+3XY²-Y³)-X³=-3X²Y+3XY²-Y³
=-3xy(x²-2xy+4y²)
(-3xy)立方*2x立方/(-3x平方y)=-27x^3y^3*2x^3/(-3x^2y)=18x^4y^2
因为(x的立方+3x的平方y-2xy的平方)-(y的立方-2xy的平方+x的立方)=x的立方+3x的平方y-2xy的平方-y的立方+2xy的平方-x的立方=3x平方y-y立方只含有1个x平方所以无论x
(2x立方-3x平方y-2xy平方)-(X立方-2XY²)+(-X立方+3X²Y-Y立方)=2x³-3x²y-2xy²-x³+2xy
x^2y-xy^2+x^3-y^3=x^2y-y^3+x^3-xy^2=y(x^2-y^2)+x(x^2-y^2)=(x+y)(x^2-y^2)=(x+y)^2(x-y)不懂还可以问(⊙o⊙)哦再问:
=-x³y+12x^4y^4-12x^4y^4=-x³y
6X立方-3X平方-4Xy+7+5X平方+8xy-6x立方y-10=6x³+2x²+4xy-6x³y-10
令-4x²+3xy+2y²=0即4x²-3xy-2y²=0解得x=﹙3±√41﹚y/8∴-4x²+3xy+2y²=﹣4[x-﹙3+√41﹚y