先化简再求值(x-3x x 1)除-搜答案-拍题作业网

[(x-4)/(x^2-1)]÷[(x^2-3x-4)/(x^2+2x+1)]+1/(x-1)=[(x-4)/(x+1)(x-1)]÷[(x-4)(x+1)/(x+1)^2]+1/(x-1)=[(x-

[(x+2)/(x^2-2x)-(x-1)/(x^2-4x+4)]÷[(4-x)/x]=[(x+2)/x(x-2)-(x-1)/(x-2)²]÷[(4-x)/x]=[(x+2)(x-2)-x

3x^3-[-x^2-2(x-x^6)]=3x^3+x^2+2(x-x^6)=3x^3+x^2+2x-2x^6x=-1原式=-3+1-2-2=-6

(x分之X的平方+4-4)除的X平方+2x分之X的平方-4=[(x²+4)/x-4]÷[(x²-4)/(x²+2x)]=[(x²-4x+4)/x]÷[(x+2)

您好：原式=[x/(x-1)²-1/(x-1)]*（x²-1）/2=1/2[x/(x-1)²-1/(x-1)]*(x+1)(x-1)=1/2[x(x+1)/(x-1)-(

[2x-6/x-2]除于[x-3/x²-4x+4]=[2（x-3/x-2）]/[x-3/(x-2)^2]=2(x-2)把x=3代人得出值等于2

原式=1/4y[x^2-4*y^2-(x^2+8*xy+16y^2)]=1/4y(-8*xy-20*y^2)=-2x-5y代入得：原式=(-2)*(-2)-5(-3)=19

3x-3/x平方-1除3x/x+1减1/x-1=3(x-1)/[(x-1)(x+1)]*(x+1)/3x-1/(x-1)=1/x-1/(x-1)=1/2-1=-1/2

是{（x+y）2-（x+y）（x+3y）-5y}/2y=【（x+y）（2-x-3y）-5y】/2y=(x+y)(2-x-3y)/5y-2.5带入数字（-2+1/2）(2+2-1.5)/2.5-2.5=

[x+1-15/(x-1)]÷[(x^2-4x)/(x^2-x)]=[(x^2-1-15)/(x-1)]÷[x(x-4)/x(x-1)]=[(x^2-16)/(x-1)]÷[(x-4)/(x-1)]=

[(X-Y)²+(X+Y)(X-Y)]÷2X=(X²-2XY+Y²+X²-Y²)÷2X=(2X²-2XY)÷2X=X-Y=3-2=1

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[3x/(x+2)-x/(x-2)]÷2x/(x^2-4)分子分母同时乘以x²-4=[3x(x-2)-x(x+2)]/2x=(3x²-6x-x²-2x)/2x=(2x&#

(x-x-4\x-3)除(x的平方-4\x-3)=[x(x-3)-(x-4)]／﹙x-3﹚÷﹙x+2﹚﹙x-2﹚／﹙x-3﹚=﹙x²-4x+4﹚／﹙x-3﹚*﹙x-3﹚／﹙x+2﹚﹙x-2﹚

x²+5x+6/x+3除x²-4/X-3-1=(X+3)(X+2)/X+3除(X+2)(X-2)/X-3-1=X-3/X-2-1=-1/X-2x=根号3代入得-1/根号3-2

(x-4)(x-2)-(x-1)(x-3)=x²-6x+8-x²+4x-3=-2x+5当x=-5/2时原式=-2*(-5/2)+5=5+5=10

原式=-10/3√12x^2*3x/y*x/4y=-10x^2/y=-10/2=-5

原式=(x²-4y²-x²-4xy-4y²)×(2/y)=(-8y²-4xy)×(2/y)=-16y-8x=-4+8=4