-(a²-2ab).9a²-(9ab³ 12a^4b²) 3ab
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(a-b)(a^2+ab+b²)=a³+a²b+ab²-a²b-ab²-b²=a³-b³(题目中最后的b应为b
ab的平方+2ab+a=a(b²+2b+1)=a(b+1)²
=a(a+b)/(a+b)^=a/a+
因为|a-4|+(b-9)^2=0,所以|a-4|=0,(b-9)^2=0,即a=4,b=9所以a^2+ab/b^2*a-ab/a^2-b^2=a(a+b)a(a-b)/[b²(a-b)(a
解题思路:利用整体求解,注意不要指望把ab的值求出,只是利用所提供条件进行变形得到。解题过程:a²-4ab+4b²-2a+4b=(a-2b)^2-2(a-2b)a(a+1)-(a²+2b)=1化简(展
解题思路:先去括号,再合并同类项即可,注意去括号时符号的变化解题过程:
a²-{-4ab+(ab-a²)}-2ab=a²-﹛-4ab+ab-a²﹜-2ab=a²+4ab-ab+a²-2ab=a²+a
a-6ab+9ab²=a(1-6b+9b^2)=a(1-3b)^2x²-x+1/4=(x-1/*2)^29x²-6x+1=(3x-1)^2x²+7x+6=(x+
从今年将拿出就个人个人很听话再问:无聊再答:哎刚刚做个任务而已啦。。。原式=[a(9a-6b)+b²]/[a(3a-b)]把a约掉=[9a-6b+(b²/a)]/(3a-b)=a[
因为a+b≥2√(ab),则:1/(a+b)≤1/[2√(ab)],所以:2ab/(a+b)≤2ab/[2√(ab)]=√ab,即:2ab/[a+b]≤√(ab)
(3a^2+2ab)-2(a+ab)=3a²+2ab-2a-2ab=3a²-2a不懂得欢迎追问...
网友们都懒得做哈哈第一题3B-2
3(a^2-ab)-5(ab+2a^2-1)=3a^2-3ab-5ab-10a^2+5=-8ab-7a^2+5施主,我看你骨骼清奇,器宇轩昂,且有慧根,乃是万中无一的武林奇才.潜心修习,将来必成大器,
3(-ab+2a)-(3a-b)+3ab=-3ab+6a-3a+b+3ab=3a+
原式=2a^2+3ab+b^2-a^2-ab=a^2+2ab+b^2=(a+b)^2
1、(1/a-1/b)^2/(1/a^2-1/b^2)=(1/a-1/b)^2/(1/a-1/b)*(1/a+1/b)=(1/a-1/b)/(1/a+1/b)=(b-a)/(a+b)
(3a-2b)(3a+2b)(3a+2b)-(3a+2b)(3a-2b)(3a-2b)=(3a-2b)(3a+2b)4
=a(3a-b)/(3a-b)^2=a/(3a-b)
解-3ab-4a²+3a²+5ab=(-4a²+3a²)+(5ab-3ab)=-a²+2a
由(√a+√b)²≥0∴a+b-2√ab≥0∴a+b≥2√ab1/(a+b)≤1/2√ab.∴2ab/a+b≤2ab/2√ab=√ab.所以2ab/a+b≤√a