以下程序判断输入的数能否被3或7整除

#includevoidmain(){intn;printf("input:\n");scanf("%d",&n);if(n%3==0&&n%5==0)printf("yes\n");elseprin

#includevoidmain(){intn;scanf("%d",&n);if(n%3==0&&n%5==0&&n%7==0)printf("3\n");elseif(n%3==0&&n%5==0

#include#includevoidmain(){floata,b,c,s,area;printf("pleaseinputa,b,c\n");scanf("%f%f%f",&a,&b,&c);i

C语言?#include"stdio.h"intmain(){intnum,i=0;printf("请输入一个数字\n");scanf("%d",&num);while(num){\x05++i;\x

Subabc()'输入三角形三个边长,计算其面积Dima,b,c,sDos=InputBox("请输入三角形的三个边长,用半角逗号分隔."&Chr(13)&"输入-1时结束程序.")IfVal(s)=

额,这个更简单了if(i%7==0)

#includeintmain(intargc,char*argv[]){intnum;printf("输入一整数:");scanf("%d",&num);if(num%3==0&&num%5==0&

importjava.util.Scanner;publicclassTriangle{publicstaticvoidmain(String[]args){\x09inta;\x09intb;\x0

我把SCANF里的中文去掉就正常了.

#include"stdio.h"main(){intx;printf("请输入一个数字:");scanf("%d",&x);if(x%3==0)printf("该数字能被3整除.");if(x%5=

if(x%3==0)y=3;if(x%5==0)y=5;if(x%7==0)y=7;if(x%7==0&&x%5==0&&x%3==0)y=15;if(x%7==0&&x%5==0)y=12;if(x

#includevoidmain(){intnumber;intre[3];inti=0;scanf("%d",&number);if(number%3==0){re[i]=3;i++}if(numb

voidmain(){intn;printf("请输入一个整数:");scanf("%d",&n);if(n%3==0&&n%5==0&&n%7==0)printf("\n此数能被3,5,7整除\n"

oolfun(inti)//判断i{if(i%3==0)returntrue;returnfalse;}

两边之和大于第三边两边之差小于第三边符合三角形两边相等为等腰三边相等为等边if(a+b)>cTHENif(a-b)

PrivateSubCommand1_Click()DimaAsInteger,bAsInteger,cAsInteger,dAsIntegera=Val(InputBox("输入三位整数"))b=I

k%3==0||k%7==0no\n

#include#includedoublemianji(doublea,doubleb,doublec);voidmain(){doublea,b,c;kaishi:coutb>>c;if((a>0

算法程序：#includevoidmain(){inta,b;printf("inputa,b:(a>b)\n");scanf("%d,%d",&a,&b);if(a%b==0)printf("OK\

个位数字如果是偶数(也就是双数)就能被称2整除.即:02468