从键盘输入十个数分别输出正数和负数和

求和应当是：#include#includemain(){inti,up=0,down=0,data[10];for(i=0,i0)up+=data[i];elsedown+=data[i];}pri

#inlcudevoidmain(){inta[6];inti,j,max=0,sum=0;doubleavg=0.0;printf("请输入六个数：\n");for(i=0;imax)max=a[i

floata,b,sum,ver;puts("pleaseentertwonumber:");scanf("%f,%f",&a,&b);sum=a+b;ver=sum/2;printf("sum=%f

#include"stdio.h"main(){inta,b;printf("请输入两个整数(a,b)：");scanf("%d,%d",&a,&b);printf("和：%d\n",a+b);pri

#includevoidmain(){inta[10];for(inti=0;i

dimarray(),iasinteger,jasintegerdimmin_iasinteger,max_jasinteger'用来标注数组中最小值和最大值的下标redimarray(10)=[1,

#includevoidmain(){inta[10];floataver=0;for(inti=0;i

#include"stdio.h"voidmain(){inta[3],i,max,min;max=min=a[0];printf("请输入3个数：\n");for(i=0;i

#include#include#defineN5intmain(){inti,j,a[10],sum=0,temp;floataverage;for(i=0;i

#includeintmain(){intnum;inta,b,c;scanf("%d",&num);a=num/100;b=(num%100)/10;c=num%10;printf("a=%d,b=

#include#includeintmain(){scanf("%lf",&k);printf("%d\n",(int)sqrt(k));}

好久没写过汇编的程序了,代码估计我现在做不出来,能告诉你下原理~把3位十进制分别读入后,存到内存的是相应符号的ASC2码,将这个符号asc码转成数字的asc码比如9存进去的是39H要变成1001,也就

#includeintmain(){inti,a,max,min;couta;max=min=a;for(i=1;i>a;if(maxa)min=a;}cout再问：那这句话为什么要改成for(i=1

#includeintmain(){inta,b,c;intmin,max;scanf("%d%d%d",&a,&b,&c);if(amax)max=c;printf("%d%d%d",max,a+b

main(){intmax,min,x,i;scanf("%d",&x);max=min=x;for(i=0;imax)max=x;if(x

ntmain(intargc,char*argv[]){charsound[10][5]={"yi","er","san","si","wu","liu","qi","ba","jiu","shi"}

importjava.util.Scanner;publicclassDemo{publicstaticvoidmain(String[]args){intx=newScanner(System.in

#include"stdio.h"voidmain(){inta[15];printf("Pleaseinput15numbers:\n");for(inti=0;i

#include<malloc.h>#include<string.h>#include<math.h>#defineMAX(a,b)(a>b?a:b)#de

#include//求a和b最大公约数：intyue(inta,intb){intk=1;intt=a>b?b:a;//a大取b,否则取afor(inti=1;i