2)从键盘输入五个数,按照从小到大的顺序输出
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importjava.util.Arrays;importjava.util.Scanner;publicclassDataCompare{\x09publicstaticvoidmain(Strin
#includeusingnamespacestd;intmain(){inti,n,s=0;coutn;s=0;for(i=1;i
floata,b,sum,ver;puts("pleaseentertwonumber:");scanf("%f,%f",&a,&b);sum=a+b;ver=sum/2;printf("sum=%f
#include#includevoidmain(){inti,j,n,number=1,a[30][30];printf("PleaseinputanumberN:");scanf("%d",&n)
#includevoidmain(){\x09intnum[100];\x09inti;\x09for(i=0;i
经过调试,编写程序写上如下代码可以实现你的要求:cleari=15dimea(i)forn=1to15"第",n,"个数据:"input"请输入数字后按回车键(Enter↓):"toaifn=1b=a
*vfp中计算n(从键盘输入的正整数)个实数(从键盘输入)去掉其中最大数和最小数之后的平均值的程序怎么写CLEARINPUT"输入共N个(正整数)个数字:"TOnNDIMENSIONsz(nN)INP
#includeusingnamespacestd;intmain(){char*str=newchar[255];cin>>str;cout再问:看不等,我刚学编程再答:把输入的数字放到一个指针数组
#includeintmain(){inta,b,c;intmin,max;scanf("%d%d%d",&a,&b,&c);if(amax)max=c;printf("%d%d%d",max,a+b
main(){intmax,min,x,i;scanf("%d",&x);max=min=x;for(i=0;imax)max=x;if(x
//uses math;//为了它的使用max 和min 函数;//在public处,添加一个自定义排序函数sort,原型为:function sort(a:i
#include<stdio.h>void main(){ int a[5]={0}; int i,j,t; printf(&q
1:1/4=8:2
dimensions(10)fori=1to10input"请输入s(i)的值"tos(i)nexti
#includevoidmain(){intn,i,j,k,m;floats=0,t;i=1,j=2;printf("输入n:");scanf("%d",&n);for(m=1;m
clearinput"请输入一个数:"toxifx%2=1?"是奇数"else?"是偶数"endif第2题是什么?
#includeintmain(){inta[20][20];inti,j,n,x,y,x1,y1,n1,sum;printf("请你输入n:");scanf("%d",&n);n1=n;sum=n;
#includeintfindmax(inta,intb){if(a>b)returna;elsereturnb;}intmain(){inta,b,c;scanf("%d%d%d",
voidmax(inta,intb,intc){intt;q;t=a>=b?a:b;q=t>=c?t:c;printf("%d\n",q);}
#include#includeintmain(){floata[10];inti;floatave;//平均值floatsum=0.0;//和for(i=0;i