(3x^-5y)(x^ 2x-3)怎么做

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/28 21:43:48
(2x -y)(3x-2y)+(y-x)(2x-5y)

(2x-y)(3x-2y)+(y-x)(2x-5y)=6x²-4xy-3xy+2y²+2xy-5y²-2x²+5xy=4x²-3y²

[(x+2y)^2 -(x+y)(3x-y)-5y^2]÷2x

原式=(x²+4xy+4y²-3x²-2xy+y²-5y²)÷2x=(-2x²+2xy)÷2x=-x+y再问:x=-2y=二分之一再答:=5

计算(x^8-x^7y+x^5y^3-x^4y^4+x^3y^5-x^y^7+y^8)(x^2+xy+y^2)

-x^y^7+y^8)(这里有问题,x的几次方?再问:就是一次方再答:(x^8-x^7y+x^5y^3-x^4y^4+x^3y^5-xy^7+y^8)(x^2+xy+y^2)=(x^8-x^7y+x^

6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5

设x-y=mx+y=n则6m-2n=143m+n=5解得m=2n=-1即x-y=2x+y=-1解得x=1/2y=-3/2

3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27

化简得:-x+7y=11①7x+3y=27②①式×7得:-7x+49y=77③②+③得:52y=104∴y=2代入①得:x=3∴x=3,y=2再问:亲,是代入法哦!再答:代入法①式得3x+3y-4x+

因式分解3x^2(x-y)+6x(y-x)

3x^2(x-y)+6x(y-x)=3x^2(x-y)-6x(x-y)=(x-y)(3x^2-6x)=3x(x-y)(x-2)

2(2x+3y)(3x+2y)-(6x-y)(2x-5y)

2(2x+3y)(3x+2y)-(6x-y)(2x-5y)=12x^2+26xy+12y^2-(12x^2-32xy+5y^2)=12x^2+26xy+12y^2-12x^2+32xy-5y^2=58

(x+2)(x+3) (x-4)(x+1) (y+4)(y-2) (y-5)(y-3)

(x+2)(x+3)=x²+5x+6(x-4)(x+1)=x²-3x-4(y+4)(y-2)=y²+2y-8(y-5)(y-3)=y²-8y+15x²

[(x+2y)(x-2y)-(2x-y)^2+(3x-y))2x-5y)]/(-x)

[(x+2y)(x-2y)-(2x-y)^2+(3x-y))2x-5y)]/(-x)=(x²-4y²)-(4x²-4xy+y²)+(6x²-17xy+

已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)

因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6

数学(x-y)^5*(y-x)^3*(x-y)^2

(x-y)^5*(y-x)^3*(x-y)^2=-(x-y)^5*(x-y)^3*(x-y)^2=-(x-y)^(5+3+2)=-(x-y)^10

(2x-y)(3x-2y)+(y-x)(2x+5y)

/>(2x-y)(3x-2y)+(y-x)(2x+5y)=6x²-3xy-4xy+2y²+5y²-2x²+5xy-2xy=6x²-2x²-7

7x+[-3x-3(x-2y)]-[5x-(2x-y)]

7x+[-3x-3(x-2y)]-[5x-(2x-y)]=7X+[-3X-3X+6Y]-[5X-2X+Y]=7X-3X-3X+6Y-5X+2X-Y=5Y-2X

先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y

解(x-y)(x+y)-(x-2y)²+x(3x-5y)-(x-y)(x-2y)=(x²-y²)-(x²-4xy+4y²)+(3x²-5xy

有这样一道题:"计算(2*x*x*x-3*x*x*y-2*x*y*y)-(x*x*x-2*x*y*y+y*y*y)+【-

解代数式得:-3x的平方y-2y的三次方因为1/2的平方=-1/2的平方,所以结果仍正确给分吧!嘿嘿!

5(x-y)^2-(x-y)-8(x-y)^2-3(x-y)

原式=(5-8)(x-y)^2-(1+3)(x-y)=-3(x-y)^2-4(x-y)

用递归法求y=x-(x*x*x/3!)+(x*x*x*x*x/5!)-(x*x*x*x*x*x*x/7!)+.

#includesintjiesheng(intn)//用于计算阶乘如:3!{if(n=1)rerunn;returnn*hh(n-1)}doubledigui(intn,intx)//用以计算y=x

化简:[(x+2y)^2-(x+y)(3x-y)-5y^2]/2x

[(x+2y)^2-(x+y)(3x-y)-5y^2]/2x=[x^2+4xy+4y^2-3x^2-2xy+y^2-5y^2]/2x=(-2x^2+2xy)/2x=y-x

(2X-3y)-(5x-y)

(2X-3y)-(5x-y)=2x-3y-5x+y=2x-5x-3y+y=(2x-5x)+(-3y+y)=-3x-2y这样写总是全过程了吧