(2x y)(2x-y)-4(x-2y)的平方-搜答案-拍题作业网

对.前提是x不等于y

(x+y-2xy)(x+y-2)+(1-xy)^2=(x+y)^2-2(1+xy)(x+y)+4xy+1-2xy+x^2y^2=(x+y)^2-2(1+xy)(x+y)+(1+xy)^2=(x+y)^

因为x-y=4xy所以x-2xy-y=2xy2x+3xy-2y=11xyx-2xy-y分之2x+3xy-2y=5.5

(-3x^y+2xy)-(4x^+xy)=-3x^y+2xy-4x^-xy=-3x^y+xy-4x^所以填上-3x^y+xy-4x^

4xy-(x+y)^2/xy(x+y)(x-y)÷x^2+xy-2y^2/x^2y+2xy^2=(4xy-x²-2xy-y²)/[xy(x+y)(x-y)]÷[(x-y)(x+2y

=xy(x-y)×[-xy/(x-y)]=-(xy)²=-x²y²

xy-[x+2y+(0.5x-2)×(y-2)]=24xy-[x+2y+0.5xy-x-2y+4]=24xy-x-2y-0.5xy+x+2y-4=24xy-0.5xy=24+40.5xy=28xy=5

原式=[4(x+y)-2xy]分之[(x+y)+xy]=[4(3xy)-2xy]分之[(3xy)+xy]=10xy分之2xy=5分之1

【x²+xy/（x-y）】/【xy/（x-y）】=【x²（x-y）/（x-y）+xy/（x-y）】/【xy/（x-y）】={【x²（x-y）+xy】/（x-y）}/【xy

x^3y(-4y)^2+(-7xy)^2*(-xy)-5xy^3*(-3x)^2=16x^3y^3-49x^3y^3-45^3y^3=-78x^3y^3如果本题有什么不明白可以追问,

(x^-4y^)/(x^+2xy+y^)/(x+2y)/(2x^+2xy)=1.=3(a-b)/(10ab)*(25a^2b^3)/((a+b)(a-b))=15/2*(ab^2)/(a+

(2x²y-3xy²)-3(x²y-2xy²)+2（x²y-4xy²）=2x²y-3xy²-3x²y+6xy&

(-x-2y)(x²-2xy+4y²)

原式=-(x+2y)*(x^2-2xy+4y^2)=-(x^3+(2y)^3)=-x^3-8y^3

（4xy+12y)+[7x-(3xy+4y-x)]=4xy+12y+7x-3xy-4y+x=xy+8x+8y=xy+8(x+y)=(-2)+8*3=-2+24=22

即(x-2y)²=0x-2y=0所以x=2y所以原式=(2x²+2xy-xy-y²)/(4x²-4xy+y²)=(2x²+xy-y²

=[-(X-Y)/XY(X=Y)]*[XY/(X-Y)]=-1/(X+Y)=-1/25

∵x-y=4xy，∴2x+3xy-2yx-2xy-y=2(x-y)+3xyx-y-2xy=8xy+3xy4xy-2xy=112．故答案为：112．

原式=3x²y+xy²-2xy²+4x²y-x²y+2xy²=3x²y+4²y-x²y+xy²-2x

x^2y+4xy+4y

x^2y+4xy+4y=y(x²+4x+4)=y(x+2)²

题目好像有问题再问：没有问题的